Selfrunning cold electricity circuit from Dr.Stiffler

[Loki67671]

Dr Stiffler,
Absolutely........I agree, but you know I have to fiddle with this circuit anyway. I'm usually trying to break software and systems not diving back into oscillator design. I'm actually enjoying this and I still want to at least reproduce the results you have presented thus far. It really is a cool circuit..........good luck with the independent V&V.

Hmmmmm........Colpitts Oscillator.............Electrostatic coupling into??? Wonder if anyone has tried this on their TPU? I have about three or four of them laying around.

[allcanadian]

@Dr.stiffler
It looks as if your output has increased with the use of a loose coupling?, Tesla made remarks to the effect that when using these types of currents problems arise in tight coupled coils due to distributed capacitance which can be resolved by adding capacitance in series with or parallel to the secondaries.This seems reasonable when we consider the fields we are dealing with and that inductance should be counteracted, at which point we should also consider the rate of vibration in the secondary itself as it does not necessarilty have to match your primary but could have a resonant relationship to it.
Best Regards

[EMdevices]

*removed*  EM

[Koen1]

Sorry to jump in like this,
but who agrees with the analysis given on Peswiki ??
(http://peswiki.com/index.php/OS:Stiffler_Cold_Electricity_Circuit):

comments on video 2 by PM:

This circuit is similar to a very common circuit used by thousands of people everyday to power the flash lamps in disposable cameras.

The equation Ronald Stiffler is using for energy in the capacitor is based on the voltage of an open circuit capacitor. The measurements seem to be of the voltage being applied to the capacitor in the circuit. Depending on the circuit, these can be quite different. Therefore his capacitor energy calculations are probably incorrect.

The readings shown on the power supply are 12 volts and 0.120 amps. Power in watts is volts times amps. Power is an instantaneous reading. Energy is power times seconds. Energy is an average reading over time. The power going into the circuit is 12 volts x 0.120 amps = 1.44 watts constantly. The energy going into the circuit is the average power per second. Since the power going into the circuit is constant, the average value will be the same as the constant value. Thus the energy going into the circuit is 1.44 watts-seconds where 1.44 watts is the average value of the power during each second. This energy is then converted to a higher voltage by use of the transformer (apparently to about 114 volts). Since energy is conserved, the energy coming out of the transformer is also 1.44 watt-seconds (with some losses due to heat). This energy can be stored in a capacitor and removed either slowly or quickly as desired. In this case all of the energy added to the capacitor in each second is then removed at the end of the second (if the light is pulsed once per second as stated in the video). Thus an energy of 1.44 watt-seconds is added to and then removed from the capacitor each second. It is not given, but the bulb appears to be on for about 1/10 of each second. Assuming this value, then the average watts going into the bulb during that 1/10 of a second must be 10 x 1.44 = 14.4 watts in order for the energy to be 1.44 watt-seconds (with 0 watts going into bulb when it is off). Remember, energy is the average value of the instantaneous power in watts that is applied during the second. In this case, to get the average power put into the bulb the power in each 1/10 of the second is summed and then divided by 10 > 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 14.4 = 14.4 and 14.4/10 = 1.44. Since the bulb is a 15 watt bulb, it will be bright during the 1/10 second it is consuming 14.4 watts. Thus the circuit performance can easily be explained without ?cold electricity? or ?over unity?.

Note that the primary of the transformer is being fed with an RF frequency signal. It is unclear if this is deliberate or if it is a parasitic oscillation. The open lead on the secondary of the transformer is not actually unconnected at RF frequencies but is connected to other parts of the circuit by the parasitic capacitance of the lead.

So what he's saying is that Stifflers circuit is not at all OU...
Which of course is in direct contradiction with the claim that this circuit is a self-running "cold electricity" OU circuit...
And, by the way, also in conflict with Stefans own statement

So ouput / input is around 170. (Stefan Hartmann; Oct. 11)

.

Anyone?

[EMdevices]

*removed* EM