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Overunity Machines Forum



Selfrunning cold electricity circuit from Dr.Stiffler

Started by hartiberlin, October 11, 2007, 05:28:41 PM

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quarktoo

#2840
July 05, 2010, 02:16:35 AM
Quote from: ramset on July 04, 2010, 09:26:11 AM
Quarktoo
Is one wire electrolysis in distilled water nothing special?
{last time I looked I think that was the claim[I could be wrong]]

Chet

It would have been until John Kanzius did it with zero wires. After that... not so special...

exnihiloest

#2841
July 05, 2010, 03:17:00 AM
Quote from: ramset on July 04, 2010, 09:26:11 AM
...
Is one wire electrolysis in distilled water nothing special?
...

It is not a one wire electrolysis.
There are the two diode electrodes.


Pirate88179

#2842
July 06, 2010, 03:13:54 AM
Quote from: exnihiloest on July 05, 2010, 03:17:00 AM
It is not a one wire electrolysis.
There are the two diode electrodes.

To be more exact, it is a no wire set-up as the diode is not connected to anything at all.  Also, the bubbles only emanate from one end of the diode and not the other, so I believe that makes this a bit unusual.

Bill
See the Joule thief Circuit Diagrams, etc. topic here:
http://www.overunity.com/index.php?topic=6942.0;topicseen

Sprocket

#2843
July 06, 2010, 10:26:50 PM
The 'unusualness' I see is that Dr. Stiffler is implying that irrespective of the number of diodes used, there will be no increase in input power!  Generating hydrogen like this is also cool I suppose! :)

Also, I don't think that Dr. Stiffler somehow 'forgot' about using just one diode tied to something with lots of spikes - mucho diodes would appear a pre-requisite...

quarktoo

#2844
July 15, 2010, 06:14:41 AM
Quote from: Pirate88179 on July 06, 2010, 03:13:54 AM
To be more exact, it is a no wire set-up as the diode is not connected to anything at all.  Also, the bubbles only emanate from one end of the diode and not the other, so I believe that makes this a bit unusual.

Bill

Both electrodes produce gas and he points this out in latter videos. Stiffler places the copper ring near one end of the diode and the plates of a capacitor do not distribute charge equally and so there is a capacitive connection to the diode which is as real as a copper wire connection. Stiffler's claim that it is not Faraday electrolysis does not appear to be accurate.

Don't get me wrong, I am always interested in what he is up to which seems centered around capacitive inductance.

It is also fair to point out that the copper ring, shorted or not, at high frequency is an electromagnet when surrounding the steel lead of the diode which is a core and that is an electromagnet by definition. The diode creates the dipole.
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