Selfrunning cold electricity circuit from Dr.Stiffler

[DrStiffler]

Here we go again, for what now the 10th year and pages and pages on this thread.

NO I AM NOT CLAIMING OU!!!
IT DOES NOT EXIST!!!!

You can not create or destroy energy. YES! I DO BELIEVE THIS.

But you can tap other forms that are not currently understood or utilized.

SO WHAT IS SO HARD HERE?

So if you can not climb out of your boxes and for a split second be open minded and look beyond you bank account (in case your getting paid to bash me) or beyond the trail of follows you might need to prove self worth, then I will not change you, AND YOU WILL NOT CHANGE ME.

Its a take it or leave it, bash me and I am now going to come right back. Guess when Hartmann closes this thing from the worthless banter, them the detractors will be smug and happy. But I will not back down, so those that are working towards something better might get a bit of help.

I'll be back.

Not bashing you only question you but your own photo's show the resistor is in series with all the other LED's you are not measuring the current through 1 LED but the total used buy them all. So do not multiply .0086 X 52 to figure wattage. Am I the only one that really looks at these things.
Not calming OU you have stated time and time again "I have OU"
@EMdevices
Look closely at the photos you will see the resistor is not across only one LED but is in series with them all.

Get a better life.........

[EMdevices]

*removed* EM

[DrZLowe7]

Here we go again, for what now the 10th year and pages and pages on this thread.

NO I AM NOT CLAIMING OU!!!
IT DOES NOT EXIST!!!!

You can not create or destroy energy. YES! I DO BELIEVE THIS.

But you can tap other forms that are not currently understood or utilized.

SO WHAT IS SO HARD HERE?

So if you can not climb out of your boxes and for a split second be open minded and look beyond you bank account (in case your getting paid to bash me) or beyond the trail of follows you might need to prove self worth, then I will not change you, AND YOU WILL NOT CHANGE ME.

Its a take it or leave it, bash me and I am now going to come right back. Guess when Hartmann closes this thing from the worthless banter, them the detractors will be smug and happy. But I will not back down, so those that are working towards something better might get a bit of help.

I'll be back.

Not bashing you only question you but your own photo's show the resistor is in series with all the other LED's you are not measuring the current through 1 LED but the total used buy them all. So do not multiply .0086 X 52 to figure wattage. Am I the only one that really looks at these things.
Not calming OU you have stated time and time again "I have OU"
@EMdevices
Look closely at the photos you will see the resistor is not across only one LED but is in series with them all.

Get a better life.........

So you can not refute what I am saying. I thought you said you would come wright back at me. Is the resistor not in series with all the other LEDs. I just pointed out what I thought was in error. The capacitor will produce DC you are correct you are measuring DC.

[EMdevices]

*removed* EM

[DrStiffler]

Ok, thank you,  then that's encouraging.    Assumptions are nothing bad as long as they're applicable and reasonable.


The break even point for OU in this case would be:

Vdiode =  0.936 watts / (8.6 mA x 52)  =  2.09

So you're assumption is well above this breakeven voltage drop / diode.      I would say you have something significant.

But to be sure, I would measure the DC voltage at the 10 uF capacitor.   If there is quite an AC ripple on it, I would filter the heck out of it with ferrites and include another capacitor if I have to. 

In my previous experimentation, I noticed typical LEDs give out quite a bit of light starting at 1.9 Volts and only get brighter from there.  I'm not insinuating your assumptions are not correct, don't missunderstand, I'm just trying to be carefull when it comes to excess energy measurements.   I made claims like this before and I later retracted.  Hopefully you won't have too.  I hope not.

EM

I have and will explain;
Across the 10uf, which may also include a 0.01uf and a 0.1uf just to be a crowd pleaser, the Z is the highest and there is an amount of RF that passes thru the diodes enough to upset DVM so I filter and measure with an analog with 20k/v loading. The reading across the 10uf reads 147.?V. To be what my numbers say it should read 156V, but I'll live with this. Also the 1 ohm sample resistor is on purpose inserted in mid string, I'm sure you know why.

@fritz
Pretty good there, getting close aren't you....