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Appears to be overunity Cicuit

Started by Spewing, October 14, 2007, 08:00:23 PM

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0 Members and 2 Guests are viewing this topic.

IronHead

Spewing  post the pulse circuit diagram you are using.

Spewing

i am not sure about the frequency, maybe someone could check it?

0.0000594 kilohertz = 0.0594 hertz

Mr.Entropy

Spewing,

Are you serious, or is this thread a mean-spirited joke?

Spewing

i have not claimed over unity, i seen something about this circuit that was unusual and i wanted to share it. i am not trying to be mean entropy

i did say it appears to be overunity, the battery want light the lite but the circuit will, that is very unusual so that is the reason for this post.

Mr.Entropy

Quote from: Spewing on October 15, 2007, 08:50:49 PM
i have not claimed over unity, i seen something about this circuit that was unusual and i wanted to share it. i am not trying to be mean entropy

i did say it appears to be overunity, the battery want light the lite but the circuit will, that is very unusual so that is the reason for this post.

Well, OK, but I don't see how you can do that kind of work without knowing Ohm's law.

The light bulb is a 60W 120V bulb.  That means that if you connect it across 120V, it'll draw 0.5 amps, because P=VI, and 120V * 0.5A = 60W.

From Ohm's law, V=IR, we know that the bulb's impedance 120V / 0.5A = 240 Ohms.  You can check that with your mutimeter.

If you connect that across 12V, it'll draw 12V / 240 Ohms = 0.05A.  Power into the bulb will be 12V * 0.05A = 0.6W, and that's probably not enough to light it.

You measured your own circuit, and saw that it draws 25 watts, which enough to push a fair bit of light out of the bulb.  You use an oscillator and a step-up transformer (a step-down backwards is a step-up) to provide that power at a much higher voltage so that the bulb will draw enough current to light.