Working Attraction Magnet Motor on Youtube!?

[Mr.Entropy]

Before asking inadequate questions first know what you're talking about.

You are amazingly brazen going on like this, and about your nonsensical SMOT "analysis" that people should "understand" before arguing with you.  Rest assured that I do know what I'm talking about, and I know, as you must, that the people who "understand" your analysis are the people that "see" the emperor's new clothes.

You are so brazen that I actually expected you to answer my question, and I'm disappointed that you did not.

Oh well,

Mr. Entropy

[Omnibus]

Before asking inadequate questions first know what you're talking about.

You are amazingly brazen going on like this, and about your nonsensical SMOT "analysis" that people should "understand" before arguing with you.  Rest assured that I do know what I'm talking about, and I know, as you must, that the people who "understand" your analysis are the people that "see" the emperor's new clothes.

You are so brazen that I actually expected you to answer my question, and I'm disappointed that you did not.

Oh well,

Mr. Entropy

No, you don't know what you're talking about so you'd better restrain from cluttering the thread.

[Pirate88179]

@ Omnibus:

To help answer Shrugged Atlas's question, would this be a fair description for where the exta energy in the SMOT goes?  As I see it...if you have a steel ball at x height and the SMOT makes it rise to X+whatever, then the potential energy of the ball has been raised and it is stored in the ball.  In other words, a one pound weight 1 foot off the ground has more potential energy than a one pound ball 6" off the ground.  Correct?  I think this is where the SMOT shows OU.

I don't really know so I am just putting this out there.  The fact that the engineering problem has not been solved, as Shrugged says, to close the loop does not preclude the extra potential energy imparted to the sphere by the SMOT in my mind.

Bill

[Omnibus]

@ Omnibus:

To help answer Shrugged Atlas's question, would this be a fair description for where the exta energy in the SMOT goes?  As I see it...if you have a steel ball at x height and the SMOT makes it rise to X+whatever, then the potential energy of the ball has been raised and it is stored in the ball.  In other words, a one pound weight 1 foot off the ground has more potential energy than a one pound ball 6" off the ground.  Correct?  I think this is where the SMOT shows OU.

I don't really know so I am just putting this out there.  The fact that the engineering problem has not been solved, as Shrugged says, to close the loop does not preclude the extra potential energy imparted to the sphere by the SMOT in my mind.

Bill

That's correct.

[shruggedatlas]

I do not believe the excess energy is being dissipated as heat.  A steel ball rolling on a ramp should not generate much heat.  I have another theory.

In a nutshell, Omnibus's position is that since the ball gains potential gravitational energy from B to C, and maintains the same potential magnetic energy from start point A and endpoint A, then there is a net overall gain in energy.

This sound good in theory, but has not been proven to be true in practice.  I think I know where the energy goes, and why it is impossible to extract any energy from the device.  I have attached a diagram below for illustration. The dark grey dots at B and C are the balls, and the larger grey circles represent a given area around the ball.  The balls and the grey areas are exactly the same sizes.

What happens is that when the ball drops from C, it exerts a greater magnetic drag on the ball, compared with the assistance that point B provides to the ball as it is raised.  If you look carefully, the amount of magnet in the grey circle near the balls appears roughly equal at points B and C.  However, at point C, there is more magnet close to the ball, because the angle is acute.  At point B, the angle is obtuse, so there is less magnet close to the ball.

I believe Omnibus's analysis assumes the magnetic force on the ball is the same at B and C.  Is that what you are claiming, Omnibus?