Muller Dynamo

[nul-points]

the following circuit of a pendulum.
this circuit can run muller dynamo?
(sorry bad english google translate)

hi d@rkenergy

that's a neat circuit!  (ESP is a good site)

i think that maybe not too good for the Muller replication, for at least 2 possible reasons:

a) it uses the gen/drive coil as the sensor - so it will not be possible to do much 'tuning' of the 'ON' pulse (especially to get 'attraction')

b) the supply is only 1.5V (and also the PNP transistor maybe too low-powered) - so there will not be much drive power


but the circuit is like an SCR - so it should give good switching action for a pendulum device

maybe on a small Muller replication you could get it to drive - but still not much adjustment 

all the best
np


http://docsfreelunch.blogspot.com

[Tudi]

...Cascaded systems are where the generator coil is tuned to yet another coil..

maybe this helps in some way : http://en.wikipedia.org/wiki/Voltage_multiplier

[chrisC]

@ keykhin,

Glad to help.  .

@ chrisC,

The 900 is just a constant from combining two equations together. The first one was the formula to convert RPMs into a frequency value, which is

f = RPM / 60.

But this equation assumes only one magnet rotating past the coil per cycle, so you add the "Poles" variable to increase the frequency. So:

f = (RPM / 60) * Poles

Then, I took the standard equation for LC resonance:

f = 1 / [2*Pi* Sqrt(LC)]

and solved it for C. Then after substituting in the RPM equation and simplifying terms, that's how I got the final formula with the 900 in the top.
..
- Jason O

Thanks Jason. I now understand. Will find time this coming weekend to test it out.

cheers
chrisC

[bolt]

.

[lumen]

The problem is that at a PF of zero, that is also how much energy you produce! This is simply a full resonate condition where you are simply reinforcing a standing wave. Any attempt to use this energy will cause the system to fall from the resonate condition.

It is more than likely that there is something else going on. With the load applied after the FWB and some voltage already stored in the load capacitor, this alters the start of the resonate wave with some delay. If the power factor was not exactly zero, then the push against the approaching rotor magnet (lenz drag) would be late, and applied at TDC to the rotor magnet.

Now there would be a real power factor that energy can be pulled from,  yet the lenz force is pushing directly on the rotor magnet and there is no place for it to go but out in the same direction as the rotor is turning.
This condition could do real work, and additional loading of the output would push the rotor faster.

In full resonance NO WORK IS DONE only the waveform gets larger because you keep adding to it!

If you draw any work from it greater than the input, it will simply die out. Even if you draw the same from it as you put in, it will die out. Nothing new here.