Muller Dynamo

[scratchrobot]

http://www.youtube.com/watch?v=9pTRtJ0jDjA

Could the position of the rectifier be important? Looks like it does 

Yes this must be it, look at the large fwbr's on the dynamo and 4 extra diodes in parallel.   
Have to get me some large surface fwbr's to try this abnormal effect.

@Arthurs, I don't know, I just try it.

diodes are beautiful things,
scratchrobot

[neptune]

@Arthurs , I will try to help . On each diagram , add a battery with positive to the top lead in the diagram . Now imagine that you hold each coil in your right hand so that your fingers point in the direction the current flows in the coil .Your THUMB will point to the north pole of the coil . Bucking means North Facing North or South facing south . So only figure D is bucking as , with battery connected as I said , top coil has a north pole facing the rotor , and bottom coil also has a north pole facing the rotor.

[wattsup]

Hi
@ plengo
@ k4zep
@ mariuscivic
@ Scratchrobot
@ chrisC
Because my language is not English,
Can not correctly understand the "bucking coils"
Please help me confirm the picture in: A, B, C, D which are "bucking configuration"
Thanks!

@Arthurs

If both coils shared the same core, it would be D so even if they are not sharing the same core, it would still be D in the way you are showing them.

wattsup

[chrisC]

Hi
@ plengo
@ k4zep
@ mariuscivic
@ Scratchrobot
@ chrisC
Because my language is not English,
Can not correctly understand the "bucking coils"
Please help me confirm the picture in: A, B, C, D which are "bucking configuration"
Thanks!

@Arthurs
Don't worry. Your English is perfectly fine. English is not my mother tonque either.
Look at _Yssuraxu_697 repy #3385 today. It's like that and I think your figure is either A or D, depending which way you bias the stator magnets. You can connect each coil to a DPDT switch and hook it up and try the four combinations that will yield the best result; if you're like me and don't remember which way I wired the coils! Hope that helps.

chrisC

[Hoppy]

@Hoppy . I think what you are trying to say is that in a series resonant circuit , at resonanance , I and V are in phase , and not as konehead says 90 degrees out of phase . This is what your diagrams imply . Am I right ?

Not my diagrams - from the internet. Anyone can learn the facts about resonance from the web.

Hoppy