Muller Dynamo

[xenomorphlabs]

Sure, I've seen the Vout to load rise as additional coil pairs are brought on line by paralleling their outputs after the FWBRs.  This is logical since we are just adding more phases of p2p pulses to the Dump Cap.

But what I am still wondering is this:  If coil pair #1 can bring the Dump Cap to say 12 V.  Have a small enough load that in the lag before coil pair #2 can reach full voltage that the Dump Cap V only drops to 11 V.  Now if coil pair #2 can only achieve 10V max to the Dump Cap, is it still able to send some current through to the small load?  Or does the 11 V in the Dump Cap suppress that current?

M.

I don't recall if you have access to an oscilloscope. But measuring the current in the path from coil pair 2's FWBR to the dump cap will clearly show. Even an ampmeter should.
Don't forget that you are working with a so-called bus (the rails paralleling the FWBRs) when summing the signals from the FWBRs.

[mondrasek]

Mo, I wonder what would happen if instead of pair #2 going to a dump cap, you fed it back into pair # 1 or its dump cap, possibly utilizing a pair of diodes ?

Not quite sure what you are getting at.  There is only one common Dump Cap.  All coil pairs feed that Dump Cap after their independent FWBRs.

The more I think about it I believe @wattsup is correct.  Even if a coil pair has a Vout lower than the V in the Dump Cap, it will still provide current to an attached load along with the current supplied by the Dump Cap.

So slight Vout differences between different coil sets is not a deal breaker.  Just not the most efficient use of the coil pairs since those with higher Vout will lug more than those with lower Vout.

M.

[mondrasek]

I don't recall if you have access to an oscilloscope. But measuring the current in the path from coil pair 2's FWBR to the dump cap will clearly show. Even an ampmeter should.
Don't forget that you are working with a so-called bus (the rails paralleling the FWBRs) when summing the signals from the FWBRs.

Yeah, I have a couple o-scopes.  But I am convinced that @wattsup is right.  It really is the same as having two batteries in series with one a bit more run down than the other.  Both will still provide current to the load.  The battery with the higher V does not block the current from the one with lower V in anyway.  Which is good overall wrt tuning to match coil pair Vout.  Not critical, just optimal within reason.

[wattsup]

Sure, I've seen the Vout to load rise as additional coil pairs are brought on line by paralleling their outputs after the FWBRs.  This is logical since we are just adding more phases of p2p pulses to the Dump Cap.

But what I am still wondering is this:  If coil pair #1 can bring the Dump Cap to say 12 V.  Have a small enough load that in the lag before coil pair #2 can reach full voltage that the Dump Cap V only drops to 11 V.  Now if coil pair #2 can only achieve 10V max to the Dump Cap, is it still able to send some current through to the small load?  Or does the 11 V in the Dump Cap suppress that current?

M.

No both are sending current in their respective percentages and even voltage in their respective percentages given one is higher then the other, just like if you doubled your load, both will still provide the output. Just think of it like you had two batteries. The first one is 11 volts, the second is 10 volts. In parallel, will the first one last longer since the second is also there? Of course it will to the percentage of each ones providing the load. Both will go down together at the same voltage rate.

Another point for guys that see their RPM increase and even drive amperage drop when a small load is applied, this is normal in many cases. The AC side of the fwbr when on an output coil is like applying a passive short circuit. So when the rotor is turning without any load, there is still a certain amount of shorting going on in the gen coils that creates a small level of drag caused by a circulating force in the gen coil via the fwbr. If you do nto realize this, you will simply think that the RPM you have at no load is the maximum the wheel can turn and you make that your base RPM. Now when you apply a small load, this liberates the gen coil on the AC side from its short and looping condition to a forward condition that reduces the drag slightly enough for the wheel to increase in RPM and even drop in amperage. But now just increase the load a little more and you are back to drag condition which is full forward AC moving through the fwbr (still having a level of bottle-necking) and then to the DC side to the load. So increase in RPM and decrease in drive amperage is not such a phenomenon to jump to the roof about. It usually will indicate that the rotor magnet to sensor position needs more fine tuning. Actually you are better to set your hall sensor for the lowest free wheeling rpm possible so that when under load, the hall sensor is still in the best position to keep the wheel turning. You should be able to see this if you put an ammeter in series with the generator coil on the AC side without a load on the DC side.  You should still see some amperage movement even though there is no load. The energy is simply circulating in a loop but also creating some drag on the rotor. 

wattsup

Added: Geez, I just saw your last post. lol

[Cap-Z-ro]

Quote from: Cap-Z-ro on Today at 06:43:23 PM

    Mo, I wonder what would happen if instead of pair #2 going to a dump cap, you fed it back into pair # 1 or its dump cap, possibly utilizing a pair of diodes ?

Quote from Mo:

" Not quite sure what you are getting at.  There is only one common Dump Cap.  All coil pairs feed that Dump Cap after their independent FWBRs."


Disregard the dump cap part then Mo, and try feeding #2 coil back into #1 coil pair, with diodes if necessary...and see if anything good happens.

Regards...