Muller Dynamo

[tinu]

@Romero,

Could at least disclose the fuel of your motor? What does it use that one has to periodically replace (besides normal tearing parts etc) for producing the output power?
and a second question
How do you understand/explain the absolute no-change in RPM when loaded? (I’m asking because such behavior is equivalent with infinite COP)
Thanks,
Tinu

[mariuscivic]

Well, remember that is a battery.From witch is sucked curent. The diference is 0,02V. Maybe that voltage went in runing the device.Or maybe not.

Now I would like to understand the strange behaviour of the device that occures when dead shorting the output.Mine behaves the same. Can anyone explain what realy happens?

Thank you.

[k4zep]

<sup>Hi Folks,

To let up for a couple min after you have been hunched over that motor for hours, take a break and watch this video on YouTube.

http://www.youtube.com/watch?v=rLDgQg6bq7o

It is the marvelous Turbo Encabulator....

Back to Work......

Respectfully
Ben K4ZEP</sup>

[bolt]

@Romero,

Could at least disclose the fuel of your motor? What does it use that one has to periodically replace (besides normal tearing parts etc) for producing the output power?
and a second question
How do you understand/explain the absolute no-change in RPM when loaded? (I’m asking because such behavior is equivalent with infinite COP)
Thanks,
Tinu

fuel? no conventional fuel it uses the ambient electron spin energy or zero point energy or anything else you want to call it.

RPM goes UP when loaded but  regulated by the DC to DC inverter otherwise it could pump more volts into the dump cap than the system can handle and start blowing things so it acts a governor.

Not anyway suggested of infinite COP. System has i/p power requirements and an o/p load so COP = o/p / i/p minus losses but it could be said once looped no energy as required by us to perform work thus alike a  solar system can be described as infinite as the sun is free but the energy comes from "somewhere"

You can check the  efficiency  of the system prior to looping. Example lets say we need 8  watts i/p and the o/p = 24 watts COP = 3 but to loop it 8 watts of the 24 must be returned back to cover the i/p leaves a nett  16 watts MINUS any losses in the return path could be say 2 watts lost. = 14 watts to power a lamp. Now you can see just because this is looped it cannot power more than 14 watts

So on you can see  a system of GAIN and a system of LOSS.  The trick is to have GAINS which cover the losses. Think about more efficient ways of converting the losses to gains rather than just pumping extra volts back to the battery.  How about the our i/p load is in SERIES with the supply what will this do when you demand more o/p power? If the battery is 12v and the coils put out just 4 volts now we have a total of 16 volts:)

[keykhin]

@ Romerouk: If you ever think to come back home, keep in mind that I have access to laser cutting, lathing, milling and CNC machines for pennies an I can build for you any part you want. Unfortunately I do not have enough time to continue research and finish my muller replica. If you will make a public demonstration, I like to join and I will ride like hell my bike all 2200 km from my home to London.