Muller Dynamo

[DeepCut]

How did you measure current? Did you place the amp meter directly across the output?
If so, then you had mA across a short with no voltage, or very little voltage.
What did your volt meter read when you took the current reading?

Yes directly across output so DMM voltage reading drops to zero or near zero.
But when i measure the current the rotor speeds up and the current draw for the drive motor goes down (acceleration under load) and when i stop measuring the current the voltage reading is higher than it was at the start but then slowly drops down again.

It's about 5.9 watts output according to the meters, but of course i have to measure the power properly with a scope, which i won't have until the new year.

I also tried putting a resistor across the FWBR output and measuring the voltage there so i could use Power=Voltage squared / resistance, but when i do that i get a zero voltage reading ?

I need help here because i've not reached this point before and it's unknown territory for me.


Cheers,

DC.

[RAD-HHO]

Yes directly across output so DMM voltage reading drops to zero or near zero.
But when i measure the current the rotor speeds up and the current draw for the drive motor goes down (acceleration under load) and when i stop measuring the current the voltage reading is higher than it was at the start but then slowly drops down again.

It's about 5.9 watts output according to the meters, but of course i have to measure the power properly with a scope, which i won't have until the new year.

I also tried putting a resistor across the FWBR output and measuring the voltage there so i could use Power=Voltage squared / resistance, but when i do that i get a zero voltage reading ?

I need help here because i've not reached this point before and it's unknown territory for me.


Cheers,

DC.

Sorry :-(
But power = voltage X current
If the voltage is near zero when the current is 13mA,
Then your power is near zero.
When your volt meter is reading 455v, you don't have any current, therefore no power.

Rick

[DeepCut]

Yes p=vi but p also = v squared / i.

Any ohms law chart will tell you that :

http://www.sengpielaudio.com/calculator-ohm.htm


Cheers,

DC.

[RAD-HHO]

Yes p=vi but p also = v squared / i.

Any ohms law chart will tell you that :

http://www.sengpielaudio.com/calculator-ohm.htm


Cheers,

DC.

P=I X E
P=E squared/R not I
P=I squared X R

Rick

[DeepCut]

Oops !

Yes i meant R, as i said originally :

"Power=Voltage squared / resistance,"

So how do i measure both simultaneoulsy ?

I know there is current there because i can light CFL's.