Meyer HV Sync-Wave (HV Water Fracturing)

[Dogs]

@Ekfugo, Thanks.

@allcanadian, I think that the trick is to use the cross over circuit. (Here's my theory..., which is mine...)
The HV positive pulsing aligns the water molecules and packs them against the positive cell wall.
After a few pulses (say 3), we switch to the circuit with the diode facing the other direction.
The HV negative pulsing will pulls at the packed molecules, and results in the disassociation.
More stuff is probably happening, but that's the main effect that we are interested in.

@Farrah Day, You aren't the only one having a problem with that circuit. I'm still have a uncertainties about it as well.
But, I think that it holds a few clues that seem to align with the Steam Resonator data in the memos.
Also the diagram indicates OV in several locations, does that mean Zero Voltage, or is it a reference to
a lines connection point (always/sometimes), it is not clear.
Or, does the 0V pointing to the center of the cavity mean that the center of the cell experiences a zero Voltage
potential given that the two pulsing opposing potentials from the inner/outer walls result in a Zero Potential in the
center of the resonant cavity.

"Traveling Voltage Wave-Action (770) of Figure (8-1) of opposite voltage polarity (+/-) of equal Voltage-Pulse Amplitudes (+Vpp/- Vpp) are zero reference to electrical ground state
(OV) by placing Amp Inhibitor Circuit (860) (Amp Inhibiting Coil 617, Blocking Diode 618, and
Magnetic Induction Core 619) between electrical ground (OV) and Center Tap of Dual Bifilar
Secondary Pickup Coils (616A/B) of VIC Matrix Circuit (690) of Figure (7-8) as to VIC Impedance
Network Circuit (620) of Figure (7-1) , as illustrated in (840) of Figure (8-10)."
- Memo WFC 427 Pg 8-7

This actually indicates that the center tapped choke w/diode is attached to ground. Which would result in a pulse on the negative side of the cell.
Which would mean that the negative side of the cell actually has 2 chokes, one fixed and one adjustible. Which would make sense, in that the addition choke resistance on the the negative terminal results in greater electron blocking on the negative side, which then results in HV within the cell.

Re: 2.86 Mega Volts is basically the result of an almost open circuit on the negative side of the cell. The electron build up because of inhibiting electron flow on the negative side of the cell.

The voltage step-up up is probably very high from my 12v to 7k transformers (higher than the rated 7k). I have not probed the voltage coming out of the transformers. Using an additional transformer's secondary as a choke results in resonance and a step up in Voltage again. And the blocking diode on the positive side, keeps electrons from back-flowing on the AC current from the transformer, which again results in HV or lots of electrons trapped between the (blocking diode/choke) and the (10 Mega Ohm Electron Inhibitor), thus across the cell.

I have also been experimenting with reduced resistance on the Electron Inhibitor (resistors less than 10 Mega Ohms) to allow some current to pass. This results in less voltage across the cell. Which means that Stan is right about making that adjustable so that voltage within the cell can be controlled (If there is a correlation between voltage and HHO production).

I definitely get Higher Voltages with I use the secondaries of the HV transformers as chokes than if I use my hand wound 1"x1" bifilar choke alone.

Just started playing around with a simulator as well (CASPOC). I'd be interested to see what the wave forms from a circuit set up like fig 8-10 looks like if the center-tapped diode/choke  simply goes to ground.

Best Regards,
-Dogs

[Farrah Day]

Hi Dogs

I'm not sure you realise just how intriguing your 2 Megavolt across your cell is.  If your transformer is upping to 7 kilovolt, then I would expect no more than 14 kilovolt due to the action of the chokes.  This is very interesting, as when using electronic software I have found that I could get around 15 kilovots pp from a 12 volt supply, but this is only achievable with an ac signal at the LC resonant frequency.  As soon as I incorporate the blocking diode, my voltage drops to twice the supply voltage.  All this is in keeping with the practical side of electronics, so you can see how unusual it is to obtain your high voltage with a blocking diode in place.  Is it possible that your diode/s are short cct?

I see 0v as being just that, zero volts - not ground. Just use old Stans stuff as a guide. Don't take anything he says too literally, and certainly don't trust his cct diagrams.

Keep us posted. All the best.

[Dogs]

@Farrah Day, For the simulation, here are some other values the,
In my tests, I'm using 3 in series diodes for the blocking diode.
The chokes (Secondary of transformer) that I am using are valued at 1H.
The difficult piece to simulate is the Water Capacitor as there is capacitance and resistance going on.
Not really sure how to make accurate measurements of these.
And then the dielectric of the water.
And, not really sure about the details of how the water cap actually reacts to the current etc...
Or does it act along the exact same lines as any capacitor? (Not sure).
On the other side of the tube, a resistor from 0 to 10 Mega Ohms.
Behind this resistor, we have a patch that goes to the non-diode side of the transformer secondary.
We also have a patch to ground or to PWM (-) which attaches to the transformer primary (-).
Then there are the settings for the appropriate frequency and gating.

I've blown my PWM again. When I have it working. I'll try to get more data to you for simulation.

-Dogs

[Farrah Day]

Hi Dogs

I think that the wfc can be simulated by a electronics software as a capacitor and resistor, but tap water as the dielectric makes for an extremely leaky capacitor, which is hard to simulate given it would make for such a poor electronic component.  Where the simulation really becomes ineffective is once ionisation takes place. The ionisation reaction can not be simulated (at least by my software), but will have a marked effect on voltage, current and indeed power.

Due to work commitments I've been away from my workshop for a few weeks, but hope to be getting my hands dirty again soon.

[Dogs]

Farrah Day,

Yes I agree. The point at which water Ionizes and the conditions under which it is willing to do so is all new territory. Especially if Stan is correct with regard to "...(pulsing electrical voltage fields of opposite polarity)..".
If this is new ground, then the details of the phenomenon are as yet unknown.

The details of what causes waters disassociation using the PWM alone, are not fully understood.
Hopefully someone performs enough experiments to and provides enough detail  so that a sensible model could be created. Any entirely empirical model would suffice. Even if we don't know all the details of how HHO production occurs, we would have some idea of how much HHO production our simulated circuit would produce.

Best,
-Dogs