Thane Heins Perepiteia.

[i_ron]

snip

Here is a number, 87

The significance?  that is the weight in pounds that it took to break the #10-32 bolt at the end of
a 45 inch arm where the fulcrum was two inches beyond that. That is a ratio of 2:45 or 22.5 times
87 pounds which is 1957 pounds. So the bolt fails at nearly a ton of weight!

For the metric folk that is 889.5 Kgs. So for a 100% safety factor "we" should limit the force on this
bolt to 444 Kg.

OK all you math wizards at what rpm does a 40 gram weight, at a radius of 115 mm, weigh 444 KG?

Picture of the destructive test setup....

Ron

[blisteringanomaly]

I may take you up on that offer Thane but it'll be a month to 2 atleast. Need a vehicle first and then we'll talk.

[i_ron]

OK all you math wizards at what rpm does a 40 gram weight, at a radius of 115 mm, weigh 444 KG?

OK, I will answer my own question...

using the formula "Force = .000341 WRN* (N squared)

http://www.muller.net/mullermachine/docs/clutch1.html

I get 155 pounds for the 1.5 ounce weight at 3600 RPM
As half of 1957 is 978 pounds that is not to be exceeded, then155 is very reasonable.

Our cut off speed  will be 9000 RPM. This works out to 971 pounds.

This is for a two times safety factor...if you want a three times safety factor then red line at
7000 RPM which puts 587 pounds on the bolt.

You are welcome

Ron

PS: the least all of you can do is to check my math... I have not always put decimal points in
the right place...  but to correct my earlier statement... it should be good to 7000 RPM and start
to chuck magnets at a little over 12000 RPM

Edit: note that the 1957 lb break point is not that of the bolt alone, but includes the fact that the
magnet cup is clamped against the disc so as long as the bolt is intact one must include the
friction of the clamped area under the cup... so keep your bolts at the proper torque, thats is
don't exceed Young's Modulus of Elasticity when tightening the bolts.

[CRANKYpants]

As half of 1957 is 978 pounds that is not to be exceeded, then155 is very reasonable.
Our cut off speed  will be 9000 RPM. This works out to 971 pounds.
This is for a two times safety factor...if you want a three times safety factor then red line at
7000 RPM which puts 587 pounds on the bolt.

You are welcome

Ron

edit: note that the 1957 lb break point is not that of the bolt alone, but includes the fact that the
magnet cup is clamped against the disc so as long as the bolt is intact one must include the
friction of the clamped area under the cup... so keep your bolts at the proper torque, thats is
don't exceed Young's Modulus of Elasticity when tightening the bolts.

OK - LET'S SEE IF I GOT THIS RIGHT?

I GOT MY '57 CHEVY BELAIR VERT WHICH IS BASICALLY HALF...
I CAN REV IT TO 9000 RPM BUT TO BE SAFE - LIMIT TO 7000...

TO KEEP THE BOLTS ON WITH ALL THAT TORQUE - I OUGHT TO GET YOUNG OVER HERE ASAP?
RIGHT?

T

[CRANKYpants]

I feel I must be firm with you, but yes, I remember that rotor. What you fail to show is 18 magnets
on it?  Can't see in the vid.

You are like a kid in a candy store... eat whats in your mouth first. That rotor was meant as a MULE.
IT has development possibilities. You have not exhausted it's life yet. When you have a firmer
understanding then we can talk. For example that rotor can be made double sided. I won't repeat
my arguments and suggestions I made off list but lets wait until your feet touch the ground again.

Ron ... having fun with you 

I DUNNO MAN - FIRST YOU WANT TO MOUNT MY COIL,AND NOW YOU ARE GETTING FIRM WITH ME!
YIKES,
I MEAN - I LOVE YOU LIKE A FATHER BUT NOT FATHER BENDOVER OR FATHER PHILMECREVICE

ANYWAY, I EAT WITH BOTH HANDS...!
HERE SHE BE! 

DO YOU WANT VIDEO WITH THAT?

FYI: YOUR ROTOTR IS 1000 TIMES BETTER!

THANKS
T