David Bowling's Continuous Charging Device

[Dbowling]

In answer to your question I have no idea why a bad battery like this would act as a negative capacitor.
Here are the things I have actually observed.
1. With a dead battery in the system, and no external load, it will charge all the batteries to "full" capacity, and then shut itself off. How it knows what "full" is, I do not know. When disconnected from the system and measured seperately at this point, batteries 1 and 2 would read around 14 volts. Battery 3 would read the same, but after sitting for a while, would read almost nothing.

2. When a load is connected to battery 3 during the charging process, the voltages on batteries 1 and 2 increase faster and climb higher as if trying to equalize with battery 3 which is in use. Almost like it wants to put an equal amount of electricity down all three "pipes" even though only one is using any electricity.

3. Some of these same things will happen when battery 3 is just a "low" battery, but eventually batteries 1 and 2 will decrease in charge rather than increase, so eventually there comes a point where it won't work anymore.

It has been said that a battery really just acts as a gate to the energy that is all around us. Perhaps a dead battery has a constant flow of electricity through it when it is part of a circuit, but when the battery is "dead" the circuit through the battery is only complete part of the time as the motor turns and pulses the circuit. When the circuit is interrupted, (Or maybe when it is complete) energy comes into the battery from the outside and flows out during the other part of the rotation of the motor. The motor is acting as a super fast switch that allows something to happen inside that dead battery.

[Groundloop]

@Dbowling,

Your theories are as good as mine, I guess. I think I have an explanation on why it shut off
the motor. At first you have two 12 volt batteries in series connected through the motor and
then to a zero volt battery. The "dead" zero volt battery now has a very high internal resistance
and the motor will not run. Then the "dead" battery gains some charge and the internal resistance
drops. The motor will now have approx. 12 volt and the lower resistance in the "dead" battery
will now allow some current to flow. When the "dead" battery has gained voltage then the voltage
potential over the motor drops. The motor stops and the "dead" battery will now loose its charge
turning to high internal resistance again. Then everything repeats.

When my two 12V7A batteries is charged then I will have approx. 168 Watt/h to play with.
(Much less in real life.) So I will hook up a 12 Volt 25 Watt light bulb as a load. If the light
bulb will light at full brightness for more than 7 hours, then there is over unity. Easy to test.
But first I must test to see if I can duplicate the on off circuit behavior.

Small steps..............

[EDIT] I have found a little more information on your motor.
See: http://www.firstwiki.net/index.php/CIM_motor
Company: http://home.cclmotors.com/welcome.aspx
A good replacement are:
The 2 1/2" CIM motor sold by BaneBots, part number M4-R0062-12 is identical to the CIM.

Groundloop.

[Dbowling]

It sounds like you know way more about electricity than I do. I'm glad. Maybe after you finish seeing if you can duplicate what I've done, you can look at another idea I have been keeping on the back burner. It is something I got from a european patent that supposedly works, but I have barely enough knowledge to put it together. I haven't yet in fact, because I haven't assembled all the parts. Radio shack does not have them all in stock and I need to order some. Not expensive, but time consuming, and time is somewhat of a premium for me most weeks. This just happens to be a really rare week so I've been trying to get as much as possible out to people. Let me know your results. I will be really interested.

[pese]

Attention
if you have 3 12 volt batteries.
AND 1 one of this is REVERS connected so : "this battery
is not an Zero Volt battery - not an "zero Ohm wire"
it is an battery, that have never 0 volt and 0 Ohm (inner resitance)
In any time anlead acid battery have his voltage , also must never
"unload". 
So the voltage (out) from this 3 batteries circuit is::

+ 12
+ 12
- 12
------
= 12 (positv voltages)

This circuit himself (withouout other parts, have the (first unbelibal) effect :
If the output is connected to an Load (Motor or bulb , resistor enc.
)
the 3 batterie will be charged !!!
(if they  was "weaker" before  as #1 and #2

[Groundloop]

@Dbowling,

After I have replicated your setup then I can take a look at your new idea. Small steps.....

@Pese,

Please read the text again. I said "dead". This means that something is not exactly, but
pretty close to reality. Then I said >a very high internal resistance< this is on the opposite
scale of zero Ohm. High Ohm equals low current. Low Ohm equals high current.

Now let us talk about a "dead" battery. It is not just a battery. It is a device that has a high
internal resistance at very low voltage. It will climb to a relative high voltage very fast when
you try to charge it. It will drop to a relative low voltage very fast when you try to discharge it.
It is behaving more like a big electrolytic capacitor than a battery, but the internal resistance
is opposite of a electrolytic capacitor regarding charge and voltage. A capacitor has a low internal
resistance when empty, a "dead" battery has a high internal resistance when empty. OK?

Groundloop.