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Interesting experiment with an transformer, 2 lamps, diodes and an magnet

Started by gast, September 06, 2005, 06:06:35 PM

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0 Members and 7 Guests are viewing this topic.

PaulLowrance

Hi Markus,

I think you're really on to something as there many other devices very similar to yours. I believe Tom Bearden's MEG uses the same principle as yours. I have to agree with Stephan that figuring out the efficiency is very important, even if you have to do it by hand.

Paul Lowrance

GM

Quote from: hartiberlin on August 29, 2006, 09:21:26 AM
yes, try to multiplicate the uVs value of the voltage measurement with the
uVs of the amperage measurement (via the shunt).
This then should give an energy value. ( power x aquisation time)
Then divide through this aquisation time and you have the realtime power.

Okay, I will do this next time... but one thing makes me thoughtful.
The description of the scopes CyclArea-Measure-function says, that areas above
the groundlevel (GND) are positive and areas beneath the ground are negative.

I am not sure that this is the right way to measure the power.
For example a pure sinuswave which have equivalent positiv and negativ areas will
nullify the measurement to zero (if I understand the function correctly)?

To go the right way I attach a part of the scopes manual which describes some
of the measurement-abilities and some of the algorithms behind the functions.
Stupidly I never had integral calculus at school, so I cannot say for sure what is the
most suitable function for the measurement. But maybe you are better trained for it? ;-)

Quote from: hartiberlin on August 29, 2006, 09:21:26 AM
P.S: Why does your scope also display uVVs so 2 Voltage "V" in the center ?
What is this ?

When I multiply 2 signals first and do a CyclArea-measurement on the resulting
waveform (which is the product of the two single waveforms), then the scope indicate
this by using "VVs" as unit.

Regards, Markus

hartiberlin

Hi Markus, versuch mal von beiden Signalen
den RMS (EFF) Wert zu multiplizieren !

Das m?sste dann dem entsprechen,
als ob Du Gleichspannungen verwendest und
DC Spannung x DC Strom multiplizierst.
Stefan Hartmann, Moderator of the overunity.com forum

Jdo300

Quote from: z_p_e on August 29, 2006, 12:28:31 AM
Jason,

The back or cemf spike created in the primary after the input pulse goes to zero, will reverse polarity in reference to the initial input pulse. As the input coil is being energized, the top of the toroid is positive wrt the bottom. When the input pulse goes low, the coil will kick back in reverse, and the bottom of the toroid will be positive wrt the top, and hence the cemf spike can energize the bulb. During the reversal, a new ISOLATED circuit is formed by the input coil, the bulb, and its series diode.

z_p_e

Thanks z_p_e, that really cleared it up for me. I had been thinking that the back emf was actually traveling backwards through the coil rather than just rushing forwards in the same direction as the input. That makes much more sense now ;D.

Quote from: tao on August 28, 2006, 11:35:13 PM
Quote from: Jdo300 on August 28, 2006, 10:32:21 PM
Hi Markus,

I attached a picture of the two toroidal cores I got today. After studying your circuit diagram, I am curious to know if you are actually sending back emf spikes to that bulb on the primary side of the toroid. I see how you have the two diodes on the incoming side of the circuit positioned to only let the power come into the coil but not surge back into the source. But where I am confused is about that second diode on the line going to the bulb. I can see that it clearly blocks the current from the source from surging into the bulb, but when the back emf spike rushes backwards through the circuit towards the source, it seems like that current would still not go into the bulb because it is trying to go backwards. Perhaps I am looking at this the wrong way but it seems more like the spikes are charging the magnetic field of the toroid and after the spike shuts off, the current continues to flow in one direction since your diode is only allowing a one-way flow of the current. Now, if my thinking is way off, could you or someone else here explain to me what is really happening?

God Bless,
Jason O

P.S. Where did you get your Tesla wire from?

I was going to buy those EXACT same toroids off ebay like two months ago, lol, $14. :)

I saw the quantity drop by 1, hehe.

EDIT: Matter of fact, I just bought a pair for $14 myself..... :)


Dimensions are (in inches): 2.60OD x 1.20ID x 1.05H.


Tao,

Yup, those are the exact dimeneions of the cores that I have. Do you know anything about them? I want to find out what kind of material they are made of and weather they can work at high frequencies or low frequencies.

God Bless,
Jason O

MeggerMan

Hi Marcus,
I had an idea this morning while standing in the shower, as you do.
What about using a DC-DC converter IC and replace the standard inductor with the toroid core and magnet.
MC34063A
These things are very efficient at around 87 percent or higher in step-up voltage mode.
I think some of the more expensive ones are as high as 95%.
You can adjust the frequency via the timing capacitor.
The output voltage is fixed by two resistors R1 and R2.
Output is up to 1.5A

http://www.farnell.com/datasheets/16073.pdf

I have used the above IC and it works very well in normal mode, but I will try it again, but with the magnet.

Description:
QuoteMC34063A
DC-to-DC Converter
Control Circuits
The MC34063A Series is a monolithic control circuit containing the
primary functions required for DC?to?DC converters. These devices
consist of an internal temperature compensated reference, comparator,
controlled duty cycle oscillator with an active current limit circuit,
driver and high current output switch. This series was specifically
designed to be incorporated in Step?Down and Step?Up and
Voltage?Inverting applications with a minimum number of external
components. Refer to Application Notes AN920A/D and AN954/D
for additional design information.
? Operation from 3.0 V to 40 V Input
? Low Standby Current
? Current Limiting
? Output Switch Current to 1.5 A
? Output Voltage Adjustable
? Frequency Operation to 100 kHz
? Precision 2% Reference

Regards

Rob