Photoionisation

[smallpotatoes]

I believe that photoionisation is the key to hydrogen production.     http://en.wikipedia.org/wiki/Photoionisation
some people are looking for a frequency, well they are right the frequency that photons are given off with energy that exceeds the energy of the valance electrons. you may recall a laser from stan mayers work used, or planned on using, to further aid production (that would be photons).  see also :  http://en.wikipedia.org/wiki/Electromagnetic_radiation
your thoughts ?

[HeairBear]

I think in Stan Meyer's case, the light was used more for absorption after the gas was ionized. The energy aperture of the atoms will absorb the photons forcing the electron/s to an outer orbit or perhaps hinder the electron from recombining if it was already plucked off.

http://spiff.rit.edu/classes/phys301/lectures/spec_lines/Atoms_Nav.swf

[smallpotatoes]

  valance electrons are furthest out and have the least energy. ionization energy number (for oxygen)   Enthalpy /kJ mol-1
1st   1313.9
2nd   3388.3
3rd   5300
4th   7469.2
5th   10989.5
6th   13326.5
7th   71330
8th   84078.0
these figures are why i think s.m. used a pulse (note these fig. are just O not a water molecule) each pulse would step up to the next electron, you can see where it becomes impractical. an electron will absorb the energy of a photon and if that energy is greater than its current "job" (as 1st 1313.9) then its emitted as a photoelectron, thus called the photoelectric effect. this is what we are doing from you noobs (me too)  to pros.
perhaps those that have been able to target specific electrons have been more efficient
@hairbear thanks! but i still think it was to target a set electrons 

[Shanti]

Well, I have to say, this is a really interesting point!

Due to my own experiments I soon realized, that the principle of SM doesn't work as he explains.
But the photo-effect could really be the answer. This would also explain the pulsing.
Then the pulsing would do nothing else, than generating a broadband EM-Wave. The atoms would absorb this EM-Energy and ionize, surely additional light (LEDs Lasers) would help. Due to some voltage potential difference, the different ionized particles would be separated so that they cannot recombine again immediately.
Then why should this be OU? Well, as we know from physics, the energy needed for ionization is dependant on many factors, e.g. temperature. If the temperature is high enough the atoms will ionize by themselves (Plasma). Due to random movement in a liquid the different atoms/molecules do have different speeds/temperature, this is why water evaporates even if the water is not heated. So if some atoms currently are already in a random high energy state and then the EM pulse is coming, then it gets ionized, but didn't need the whole energy to ionization from the EM-Wave but also from the liquid heat.
But this would mean, that the water would become very cold. And if you calculate it through this also cannot be the case, for there's simply not enough heat energy in water to get enough energy to split the water. The water would immediately freeze...
But I like the idea...