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Overunity Machines Forum



Stan Meyer WFC idea

Started by slider1, July 16, 2008, 04:36:01 PM

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slider1

July 16, 2008, 04:36:01 PM
Some of my thoughts lately.
1) Do we actually have to use the WFC within the resonant circuit?
2) Is it the step-charge and voltage that will do the work to break the covalent bond?
I think that #2 is the answer. So what if we design a seperate L/C circuit with a "step-charge" at a high voltage and feed that to the WFC?
This takes the dynamic capacitance out of the equation of the WFC and resonant circuit.

slider1

#1
July 16, 2008, 04:38:01 PM
I ran this in a simulator and it worked. Basically your lawton14 feeds a series L/C circuit. The output goes into a step-up transformer into a full wave bridge. Now you have the exact pulse train that Meyer has. You have the High voltage and current limited. You feed the output of that to your Water Cap and now as that charges you get the step-charge until it shorts out and you start again with your new pulse.
So I ran this with a L1= 5.1 uh coil and a C1= 50uf cap and at 10kHz.

One note might be to match the impedance to the WFC
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