Questions Meyers VIC circuit?

[Visual Echo]

Aughh!!  Thank you HeairBear, I owe you 5 information demerits.  I hadn't seen that drawing before, and it makes perfect sense.

So this is before his first patent (4936961) ?  It has the blocking diode but no VIC transformer (would go where the voltmeter is connected). The SCR works as the MOSFET driver in the Lawton circuit.  No adjustable second frequency, it's fixed at 120 Hz, and the gate signal is from a circuit off drawing.  The bifilar coil is connected in what I think is called common mode instead of reversing the leads on one side, differential mode?  Am I using those terms correctly?

I think Meyer realized that resonance was the key.  Does higher voltage more easily cause resonance?  Like if you tap a cymbal it might resonate at a different pitch than if you gave it a good hard whack?  In another thread you posted a link to the dune buggy video, he says he only uses 5 volts, if my awful ears don't deceive me.  So maybe voltage isn't that important, but if we use a VIC transformer it effectively isolates the water capacitor from the pulse generator making resonance easier, and higher voltage through the transformer makes it easier to hit that resonance.  The patent suggests a VIC of only 200:600 windings, not a dramatic voltage increase.  Musings of a fool (and it's me).  I don't know enough about this, if the resonance formula involves frequency, inductance, and capacitance, how does voltage fit in?  And does an isolating VIC transformer aid in allowing resonance and tuning it (by way of isolation, not voltage increase)?

It seems like it would be very hard to tune resonance with this circuit.  Pardon me if I'm rambling, and thank you for your assistance.  New information is causing consternation with elation at this station.

[slider1]

Just one of the odd things is how he talks about resonance. Like Visual Echo says it would be hard to tune resonance with this circuit. I see the reason and importance to obtain resonance, current goes to a minimum and voltage goes to infinity. When I see this circuit, it is very simple but does it resonate? As we would know Xl = Xc = resonance. Resonance or not the bifilar choke cancels the current. The pulse train charges the capacitor giving you the step charge. Is there resonance amongst the bifilar choke and the WFC? I see that every time the pulse turns off the field of the bifilar collapses current goes down, voltage goes up and stepcharges the cap. But again is this resonance? Can't we feed our pulse train to a flyback transformer to step up the voltage and then rectify it and then input that to the bifilar?? Won't this be the same??

[Visual Echo]

The Wikipedia article on "LC Circuit" helped me understand some of this ( http://en.wikipedia.org/wiki/LC_circuit ).  If the inductors are fixed value, the water capacitor changes unpredictably, and the frequency is easily controlled, finding a strong resonance point in the circuit seems difficult but not impossible.

Using a flyback transformer for the VIC transformer sounds great.  I think in this example, it would be inserted into Figure 8XA at the voltage meter.  Then the blocking diode would be in the right place.  I think this would be the same, I think the answer is yes.

I invite you to comment on my replication at http://pyroflatulence.tv/?cat=7 , I've posted some pictures and schematics using Eagle PCB CAD.

[slider1]

definitely not impossible. Just doing some math and at 120hz and 200-400pf water cell would take a pretty big inductor. I guess what I am saying is I am not sure that resonance as we know it is actually necessary? I am not sure that Meyer had his WFC resonating even though he talks about it all the time. I think one of the most important things is the stepcharge pulse train and high voltage and no current. Now the pulse is easy to create. Step that voltage up with a flyback or step-up transformer. Now when you feed that into a bifilar coil you limit current and when the pulse shuts off the field in the coil will collapse and increase the voltage potential to the plates of the WFC with no current. Every pulse to the WFC or cap will charge the cap higher creating the step-charge.
Someone help me out here, am I on the right track. Also this takes the dynamic capacitance value of the WFC out of the equation and no need for a PLL to keep this thing in resonance.