Gravity Mill - any comments to this idea?

[hartiberlin]

Hi Tbird, did you already setup your experiment or are you still needing to get parts for it ? Many thanks.

[2tiger]

Hmmm - you?re try to lift the water to a higher level via a nozzel?

This seems to me like a syringe.
Please let me compare both setups (with and without a nozzle).

Let us say the pipe has cross-section area from 1cm^2 and it is a little bit over sealevel - 5 cm.
Let us assume that the hydrostatic pressure (in the pipe full of water) is  for example 2N/cm^2 equal 0,2 bar.
How high will the water rise?
F=area x pressure  =>   1 cm^2 x 2 N/cm^2 = 2 N  =>  200 cm^3 water

h= volume / area  => 200 cm^3 / 1 cm^2  = 200 cm  (over sealevel)

Now we put a nozzle at sealevel height. The nozzle is ten times smaller than the pipe so cross-section area is
0,1 cm^2. Pressure is the same.

F=area x pressure  =>   0,1 cm^2 x 2 N/cm^2 = 0,2 N  =>  20 cm^3 water

h= volume / area  => 20 cm^3 / 0,1 cm^2  = 200 cm  (over sealevel)

That?s paradox, isn?t it ?

2Tiger

[tbird]

Hi Tbird, did you already setup your experiment or are you still needing to get parts for it ? Many thanks.

bought what i think i need, but have some building (parts) to do.

Maybe we then really have to go via a nozzle at sealevel to get it higher or use a vacuum inside the upper reservoir to suck it up.

why do you think this will make the water go higher?  will you attach a pump to the nozzle?

2tiger

why do you always use the static state of the liquid (not always, some times you don't use liquid)?  doesn't the positive pressure that causes the movement count?

tbird

[2tiger]

Tbird

why do you always use the static state of the liquid (not always, some times you don't use liquid)?  doesn't the positive pressure that causes the movement count?

But where is the positive pressure? As long the shuttle has 50% more weight than same volume of water and the exit pipe is half of the shuttle height over surface, then you have the system in balance  = static. If you want to get a positive pressure to do some useful work, than you have to make the shuttle more than 50% heavier in order to lift water more than the HALF of the shuttle height OR cut a mm from the top of the exit pipe.

So if you want to lift the water more than the height of the shuttle, you have to make him more than 100% heavier. But don?t forget the shuttle is then down on the ground and you have to lift him again by ONLY doubling its volume.

2Tiger

[tbird]

Tbird

why do you always use the static state of the liquid (not always, some times you don't use liquid)?  doesn't the positive pressure that causes the movement count?

But where is the positive pressure? As long the shuttle has 50% more weight than same volume of water and the exit pipe is half of the shuttle height over surface, then you have the system in balance  = static. If you want to get a positive pressure to do some useful work, than you have to make the shuttle more than 50% heavier in order to lift water more than the HALF of the shuttle height OR cut a mm from the top of the exit pipe.

So if you want to lift the water more than the height of the shuttle, you have to make him more than 100% heavier. But don?t forget the shuttle is then down on the ground and you have to lift him again by ONLY doubling its volume.

2Tiger

i don't have too much time right now (i'm building a test project), but if i understand you, if the exit pipe is the same height as equals the lift (different topic) but only half the volume, it can stop the force twice its size?  sounds like OU in itself since i don't see any leverage.

tbird