Why the potential energy is unlimited?

[Zhang Yalin]

Please copy the following address to see the picture.http://picasaweb.google.com/001zyl/UntitledAlbum



1. Draw water up as a doctor does medicine with a syringe by valve A, meantime valve B open, valve C closed.
2. Let the water in the cylinder out. (valve B closed, valve C open)
3. Press valve A to the cylinder bottom, close valve C, open valve B.
4. Recycle the operation continually. 
The experiment suggests E1=W(up)=G(water)h(1m),
E2=W(down)=G(water)H(9m),
The energy we get should be: E=E2-E1-W(other waste).
E2=9E1; W(other waste)=E1/1000

[TinselKoala]

Wrong.
You have to pump the water back up for the cycle to repeat.
No excess energy.

Please watch this video:
http://www.youtube.com/watch?v=EFO7OvcvUl0
Your machine is functionally identical to many other buoyancy drive ideas. You are lifting water with a plunger/pump, others are lifting it with a displacement volume in a cylinder or tank. Regardless, the work output of these systems comes from FALLING WATER which is the ultimate source of buoyancy, and the work required to lift the water back up to reset the system is ALWAYS EQUAL to the work output from the falling water. And there are always losses. So the systems cannot work, and for the exact same reason: They are GRAVITY ENGINES and gravity is conservative. You get out, what you put in, minus losses.

[Zhang Yalin]

I don’t mean what you do.
In your opining: 1(gained)=1(paid)
In mine:  9(gained)=1(paid)

[TinselKoala]

Unfortunately, in this case, I am right and you are wrong.

Your device is just a pump. If your device was overunity, all water pumps would be. But they aren't, are they.

If you don't believe me, then build your device and PROVE ME WRONG.

Or watch my videos on Buoyancy, over and over, until you get that "Eureka!" moment.

[wings]

?

http://www.metacafe.com/watch/yt-gxnHJoyrQpM/energy_from_water_floatation/