Why the potential energy is unlimited?

[TinselKoala]

When your balloon goes up, an equal volume of water must go down.
And with it, goes your "extra" work.


Very nice forest road, and I also like the giant bamboo very much.

[FreeEnergy]

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[TinselKoala]

So tell us again, please: Just where is energy supposed to come out of this system?

[Zhang Yalin]

The energy used to put the balloon into the water is: W0=G(water)h(1m)
The buoyancy of the balloon will do work: W1=G(water)H(2-10m).
Releasing the air out of the balloon only costs us W2=G(air)H.
The vacuum produced by the balloon can absorb the water up, W3=W1=G(water)H,
The energy we get should be: E=W1-W2-W(W0 and other waste).
W2=775W1; W0=W1/10;
W2=P(atmospheric pressure)V(water or air)=100,000(J). η＞80ï¼.....

[FreeEnergy]

hmm i think i get it correct me if i am wrong.
there is little pressure at bottom of the basin so because of this it is a lot easier to pump air inside the balloon with no water leaks. you just have to make the cylinder high enough to harness the kinetic energy of rising/falling of balloon to overcome the energy to pump air into the balloon.