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Overunity Machines Forum



The Young Effect, my gift to the free energy movement!

Started by captainpecan, November 16, 2008, 11:02:42 PM

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0 Members and 2 Guests are viewing this topic.

innovation_station

 8) 8) 8) 8) 8) 8) 8) 8)MY IST NEO ZAP! TECK 8) 8) 8) 8) 8) 8) 8) 8) 8)
::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::) ::)
                                       WAKE UP ALREADY

               http://www.youtube.com/watch?v=NlBg-hVTIOM


                       THE INNOVATION STATION TEAM!
To understand the action of the local condenser E in fig.2 let a single discharge be first considered. the discharge has 2 paths offered~~ one to the condenser E the other through the part L of the working circuit C. The part L  however  by virtue of its self induction  offers a strong opposition to such a sudden discharge  wile the condenser on the other hand offers no such opposition ......TESLA..

THE !STORE IS UP AND RUNNING ...  WE ARE TAKEING ORDERS ..  NOW ..   ISTEAM.CA   AND WE CAN AND WILL BUILD CUSTOM COILS ...  OF   LARGER  OUTPUT ...

CAN YOU SAY GOOD BYE TO YESTERDAY?!?!?!?!

Pirate88179

@ ist:

Great video!  (I rated 5 stars)  That looks extremely dangerous to me, ha ha.  It sounds like you have a mini arc welder there.

Bill
See the Joule thief Circuit Diagrams, etc. topic here:
http://www.overunity.com/index.php?topic=6942.0;topicseen

captainpecan

@IST

Nice...  I think I'm gonna have to duplicate that, I think I've got everything laying on my bench to do it!

wattsup

@IST

OK so, what's coming off the secondary?

Also, please open the transformer and show us the inside. We don't want to get Mac'd again. lol

Shrexes

So I'm going to assume that this topic hasn't come up and no one can prove it wrong thus making this entire thread false? Thanks.

"I think you're ignoring some key equations, like that of Work.

W = 1/2 m v^2

Since the 1/2 and Mass are constants in this experiment, we don't need to worry about them. However because velocity is squared, that's where this theory debunks. You are trying to add up figures and compare them to the original, but science says you must square them first. This happens in the equation you talk about which describes a 50% loss, and it describes it here also. The square term is used extensively in math, science, and statistics. If you want to ignore it, you have a lot of people to prove wrong yet to come.

According to your video, the distances were 221 for the full charged, and then 129 and 137 for the two half charges. What your ignoring is the angular velocity of your motor. Each time it takes roughly 4 seconds to reach that distance. This means that the 221 is traveling at a greater velocity.

55.25 - Full
32.25 - Cap 1
34.25 - Cap 2

Since everything else is held constant, we can square the velocities....

3052 - Full
1040 - Cap 1
1173 - Cap 2

Obviously, the amount of work is greatly decreased because the force is greatly decreased. I don't know if this has been brought up before, but it should. Adding up the charges means nothing unless you can prove that you're getting the same amount of work from them by adding them up individually, and you aren't."