The Young Effect, my gift to the free energy movement!

[Yucca]

@ Yucca

Last comment was not meant for you... It just landed right after your post... I have heard your disagreements, and if I remember correctly, they were respectable to say the least.  People seem to think I'm ignoring every negative comment. That is not true, some are well warranted, and those I am working on.  I am definitely picking up some tips to use.  It's just to bad people dont seem to have the tact to offer a disagreement in a way that is not demeaning and disrespectful.

Don´t worry, I understand why you´re a little ticked off with people being untactful after you have been nothing but respectful throughout. Do not let anyone get you down, that would be exactly what they want.

I like your work and presentation style, what you are learning through hands on experimenting will be set fast in your mind, you discovered on your own the effect of lowering cap switching losses by putting the diode after the coils and also realised that the more coils you put in the system the more charge you ended up with in the end, I think this is because you increased the oscillation amplitude and thus the diode could catch more overshoot.

This morning I did a crude mockup of your experiment using smaller caps and a dismembered speaker aircoil with a fast signal diode after it, I saw that a little more charge landed in cap 2 (approx 5% more V) with the coil in place. The coil rings a little because of the coils own capacitance (can see on scope) and a little of the ringing +v overshoot is captured by the diode.

Your work has caused me to learn more about cap charge transfers, I think the tricky thing about it is that when you parallel caps through what would appear to be low loss connectors that you lose half your original energy, where does it go??? This page helped me understand it all better: http://www.smpstech.com/charge.htm

I´m sure I don´t need to say it but... Keep experimenting! There are still of course things to discover that aren´t in the books.

All the best Yucca.

[alan]

Captain:

Hey, you are famous now.  I just found a video of your video on youtube.  It was made by this crazy de-bunking guy who seems about as bright (or as dumb) as the Myth Buster guys.  He claims this is just RF and everyone knows it. What a moron.  I just thought you might like to see it if you have not already.

http://www.youtube.com/watch?v=kC68qT6T5Dw

Bill

Lol, he is a clown, BUT, he doesnt say that no energy is entering the system., so debunk him using a simple faraday cage, if you feel like to.

[Koen1]

I'm sure I don't really need to post this, but still;
@Captainpecan: Nil illegitimi carborundum my friend!
You know who the guys are that are for real, you know
what you've got, and you know you can safely ignore all naysayers
and debunkers that think their physics school books can
overrule empirical test.

It is obvious one may ignore the comments of people who bring up
totally irrelevant arguments, like the nonsense arguments that
measuring only voltage in a capacitor would not be sufficient to
determine the energy contained in them, or the silly remark
that your increased output doesn't count because your pulse motor
is a pulse motor and not a DC motor, etc.

You don't even use the pulse motor in all the experiments you
posted on youtube, while you do show the charge increase...
Just goes to show that some people seem to be more interested
in contradicting you than they are in replicating the charge gain.

May I ask if you, or any of the confirmations you got from others,
have seen indications regarding the energy gain in respect to the
initial voltage used?
I ask because Bearden and Bedini mention that higher voltage
discharges result in much higher "back spikes", so it seems
possible that using a much higher voltage may result in a much
larger energy gain... ?

I was thinking of this: determine the initial voltage needed to produce
energy gain of sufficient energy to maintain a 12V DC current (either
via capacitive coupling and rectifier bridge, or perhaps directly via
a cap, etc) which can then be fed into a normal inverter and produce
normal grid-style AC for direct use in home appliances.
A transformer could be used to pump all of the charge in the seperate
capacitors back into one cap, and this third cap could then be switched
with the cap that was initially used to store the startup voltage.
This way, the initial charge could be cycled through the setup
several times untill the voltage has increased to he point where we can
"tap" some of it for use in the output part of the circuit...

[innovation_station]

I'm sure I don't really need to post this, but still;
@Captainpecan: Nil illegitimi carborundum my friend!
You know who the guys are that are for real, you know
what you've got, and you know you can safely ignore all naysayers
and debunkers that think their physics school books can
overrule empirical test.

It is obvious one may ignore the comments of people who bring up
totally irrelevant arguments, like the nonsense arguments that
measuring only voltage in a capacitor would not be sufficient to
determine the energy contained in them, or the silly remark
that your increased output doesn't count because your pulse motor
is a pulse motor and not a DC motor, etc.

You don't even use the pulse motor in all the experiments you
posted on youtube, while you do show the charge increase...
Just goes to show that some people seem to be more interested
in contradicting you than they are in replicating the charge gain.

May I ask if you, or any of the confirmations you got from others,
have seen indications regarding the energy gain in respect to the
initial voltage used?
I ask because Bearden and Bedini mention that higher voltage
discharges result in much higher "back spikes", so it seems
possible that using a much higher voltage may result in a much
larger energy gain... ?

I was thinking of this: determine the initial voltage needed to produce
energy gain of sufficient energy to maintain a 12V DC current (either
via capacitive coupling and rectifier bridge, or perhaps directly via
a cap, etc) which can then be fed into a normal inverter and produce
normal grid-style AC for direct use in home appliances.
A transformer could be used to pump all of the charge in the seperate
capacitors back into one cap, and this third cap could then be switched
with the cap that was initially used to store the startup voltage.
This way, the initial charge could be cycled through the setup
several times untill the voltage has increased to he point where we can
"tap" some of it for use in the output part of the circuit...

you make great points i just wish you knew how and where to tap the output ....




it is TOTALLY INDEPENDENT FROM THE INPUT ....  menanig the inputted engery is ONLY used to ACCESS  this HIDDEN ENGERY!!


and i said it was HEMF... THIS IS OUTPUT    just as i said of the jt ....

ist

[AbbaRue]

One interesting point is that after the first time you charge cap #1 with 18 volts,
You only need half as much power to recharge the cap back to 18 volts.
Because 9 volts or more is still left in the capacitor after it has done work with the motor.
It would be nice to find a way of using the 9 volts in cap #2 to aid in restoring energy to cap #1 again.
Right now I see the best way to use it is to discharge C2 into the motor.
So the motor gets 2 pulses of energy each time you do this. 
But just think about this a moment!!!

      "C1 STILL HAS 9 VOLTS IN IT" 

You only need to put another 9 volts into C1 to get it back to 18 volts.
Then you get 2 shots of 9 volts across the motor again.
One while discharging C1 to C2, and the other when discharging C2 directly across the motor.
That's almost double the output.


I tried a different experiment, I tried using 4 capacitors of equal value. (5600 MFD), and two 12 Volt gel cells.
I set up 2 pairs.  Each with it's own diode. And instead of running a motor I put charge back into the batteries.
I charged C1 of the 1st pair with 24 volts and discharged it through battery #1 to C2 of 1st pair.
I then charged up C1 of the 2nd pair with 24 volts and discharged it through battery #2 to C2 of the 2nd pair.
I measured the voltage across each battery before and after discharging the cap through it
I noticed a slight increase in voltage in each battery right after I did this but the voltage increase dissipated.
It was like when you connect a battery charger across a battery, right after you remove the charger
you notice the battery voltage is higher and then goes down again after the battery sits.

It would be interesting to set up a circuit that does this continuously and see if you can charge a set of batteries this way.
And the voltage stored in both C2's could be utilized to run an external circuit.
This way you can draw a current from a battery and restore the current you draw at the same time.
So the energy you use in the external circuit is completely free.

My first test was with another gel cell that was quite run down. it was a 10.9 volts. (Instead of 12.6 V)
After discharging C1 to C2 through it, I measured 11.2 volts across it.
This voltage increase dropped to 11.0 volts in about 20 seconds and seemed to stay there.
That is what prompted me to set up the 4 caps in 2 pairs that I mentioned above.