The Young Effect, my gift to the free energy movement!

[innovation_station]

i made a video for you guys.... 


ist mot sparks   http://www.youtube.com/watch?v=-CIwC0pMxQE

awsome colours 



oh i threw on a anolog meter too    lol

ist!

[AbbaRue]

Concerning charging the capacitor from the battery while using the current to do free work.
An analogy; 
You have a full container of water and and empty container. 
You can pour the water directly into the empty container or you can run it through a small turbine engine.
The water in the full container doesn't notice the turbine except that it takes longer
for the water to get into the other container.  So time is traded for energy.
The difference with the water is you would have to consume energy to lift the newly filled container
into the air so you could pour the water back into the original container.

With a capacitor, once the capacitor is charged you just need to switch over to running the motor off the charged capacitor.
The only energy consumed in doing so is used by the switching circuitry.
I'm referring to discharging the cap directly across the motor once it's charged.
If you discharge it into another capacitor then you would only get half the energy out before the motor would stop running.
Because once the two caps are at equal energy the current would stop flowing.

One question I have, how could you transfer all the energy of one cap. into another cap. ?
Would you use a switching circuit and a transformer?
The windings of the transformer would discharge the capacitor completely.
I don't see how to do this, even by stepping the voltage up, at some point the two caps
would appear to have equal charge, and the current would stop flowing.

[spinner]

Another case:

A) You have an (almost) empty battery. (let's say it shows 10V measured by DVM); forget about any losses,  use "ideal" components...(Cap, probes/wires, DVM, switcher unit,  etc.. ).(!)

1) Charge TWO IDENTICAL el. caps (e.g. 1000uF each) with that battery. (caps connected parallel with battery)
2) Disconnect those caps from the battery (when fully charged)
3) Connect those caps in series...
4) discharge the combined caps (in series) back to the same battery.

Repeat steps 1-4 as long as long as it's necessary or as long as you wish to...

Q1: Results?  What happens with the battery?  C/V/Q? Energy?

Q2: what happens if one uses a "CP's motor" in series?

Q3: Is there anything unusual happening? Where is 'FE' ?


Why so many people here are in doubt when it comes to the "theoretical" equation for Energy stored in (ideal) cap (E=CV^2/2)?

[captainpecan]

The motor acts like an inductor with rotational inertia replacing magnetic inertia. The motor does no real work in this case as it returns any current it uses to rev up back to the capacitors as it revs down. (minus frictional and resistive losses)

Load the shaft and everything changes as work is done to drive the load. Then less energy will be seen in the capacitors.

There is nothing in these circuits that is unconventional and cannot be explained by OHMS LAW and the  equations governing CHARGE and INDUCTANCE.

Those confused please open a book or do some careful lab type experiments, the fog will quickly lift.

Lack of understanding of the devices being tested leads to much confusion, and the forest is deep and dark.

I'm not so sure everything is explained already and there is nothing unconventional here.  In a conventional circuit, just the addition of a motor runs the battery down as it is direct shorted.  When you put a load on it, it drains even faster and creates a great deal of heat in the motor as lost energy is converted into heat also.

This is not what I am seeing going on in this case.  I will post my next video to try and explain.

[sparks]

Concerning charging the capacitor from the battery while using the current to do free work.
An analogy; 
You have a full container of water and and empty container. 
You can pour the water directly into the empty container or you can run it through a small turbine engine.
The water in the full container doesn't notice the turbine except that it takes longer
for the water to get into the other container.  So time is traded for energy.
The difference with the water is you would have to consume energy to lift the newly filled container
into the air so you could pour the water back into the original container.

Add a flywheel to your turbine to change it into a pump down at the end.
Electrically this is called a coil of high self inductance or choke coil.