Another wiew on gravity wheel - vacuum controlled under-water wheel

[Low-Q]

I have done some calculations.

Piston data:
length: 1m
weight: 1kilo

Vacuumtube data:
Length: 2m
Volume: 2 litres
Vacuum volume (Volume minus piston). 1 litre


Torque by the piston at:
0^o : -4,91 Nm
15^o : -4,74 Nm
30^o : -4,25 Nm
45^o : -3,47 Nm
60^o : -2,45 Nm
75^o : -1,27 Nm
90^o : 0,00 Nm
105^o : 1,27 Nm
120^o : 2,45 Nm
135^o : 3,47 Nm
150^o : 4,25 Nm
165^o : 4,74 Nm
180^o : 4,91 Nm
195^o : 4,74 Nm
210^o : 4,25 Nm
225^o : 3,47 Nm
240^o : 2,45 Nm
255^o : 1,27 Nm
270^o : 0,00 Nm
285^o : -1,27 Nm
300^o : -2,45 Nm
315^o : -3,47 Nm
330^o : -4,25 Nm
345^o : -4,74 Nm

Average piston torque: 0,00 Nm


Torque of the vacuum volume at:

0^o : 0 Nm
15^o : 0,52Nm
30^o : 1,54Nm
45^o : 2,56Nm
60^o : 3,59Nm
75^o : 4,55Nm
90^o : 4,91Nm
105^o : 4,55Nm
120^o : 3,59Nm
135^o : 2,56Nm
150^o : 1,54Nm
165^o : 0,52Nm
180^o : 0Nm

Average buoyancy torque of the vacuum volume in one revolution is 2,53Nm

Total average torque of the system is:
Vacuum Torque - Piston torque =
2,53Nm - 0 Nm = 2,53Nm

Not finished yet:
There is a link between the wheel and the mechanism that moves the piston. 270^o is the very bottom of the circular piston path, while 90^o is the very top ofthe circular piston path.
The pistons weight will force the wheel backwards from <270^o to >90^o. The pistons weight will also force the wheel forward from <90^o to >270^o with the same force.

Hmmmm ... my head hurts. Please help!!

I still, after explanations, have changed my mind, and cannot figure out how this wheel don't work.

I am sitting here with 2,53Nm left after the calculations - I know I shouldn't accodring to the laws of physics. I have concidered that the centre of each vacuum volume is closer to the axis than the ends of the tubes at any time, and that this centre is changing all the time as the wheel turns around. Just to be sure that the torque in Nm should be correct for each 15^o steps. The pistons torque is only affected by the angle, and where on the circular path the centre of the piston is present, in proportion to gravity direction (which is pretty much vertical).

If we use  several cylinders, say 12 of them, placed at every 30^o to reduce cogging. Say if we doubble the length of tube and piston, and increase the diameter to 50cm. The total torque will be 48 000Nm - What a dream

Br.

Vidar