Joule Thief

[innovation_station]

indeed mk1

i agree fully  all i have said is not 100 percent accurate ...  as i have verry limted electronics skills ... 

i think induction  ...  transformer action  but it is resonant tuned ..  so that means pulsed ... 

i know it is the colapse for sure ...

this i know beond this i have no idea

i have done 100 upon 100 of tests and such ...   

on a # of things ...  i cant be right  ...  and there is always more to it  .... 


i learn as i go ..  all i can do ..   

so  altho be it knowen    there many ways....

ist!

[jadaro2600]

@ist @all

I am not sure i come to the same conclusion as you do , the reason it light the led in both polarity is because the pickup coil winding goes in both direction , on that design if you have a pickup coil in one way it will only light the led in one way two .I think in one direction it works on induction only . That being said the important thing to see here is that you can get power out without creating a counter wave that kills efficiency, not having a scope , its really hard to confirm , but i tough its important to look at.

http://www.youtube.com/watch?v=Jiodkjo9hpk ;  ( this is ist video)

Mark

So which one is more important, the induction wave or the collapsing wave?

I liken the motion to slosh, but it seems like the flux is all sloshing more in one direction than another.

@all, btw, for anyone who answered me on my diode test questions, this reading is not in fact coming out as Ohms, the readings for one diode are different - I have a diode testing setting on the DMM, and the units it measures out are in V, which I assume is volts,....

Can anyone shed light on this?  THe resistance reading is one thing, then on the diode test setting, it is another.

For instance, on this 1n4001 diode, it has a resistance of 3.8 megaohms, and a diode test reading of 0.512 (v)

[TheNOP]

Can anyone shed light on this?  THe resistance reading is one thing, then on the diode test setting, it is another.

For instance, on this 1n4001 diode, it has a resistance of 3.8 megaohms, and a diode test reading of 0.512 (v)

it could be the diode threshole voltage.

test it with a variable source voltage.
when it start to conduct remove the diode and read the voltage then compaire.

my DMM, both, show me the resistance.

[gyulasun]

@all, btw, for anyone who answered me on my diode test questions, this reading is not in fact coming out as Ohms, the readings for one diode are different - I have a diode testing setting on the DMM, and the units it measures out are in V, which I assume is volts,....

Can anyone shed light on this?  THe resistance reading is one thing, then on the diode test setting, it is another.

For instance, on this 1n4001 diode, it has a resistance of 3.8 megaohms, and a diode test reading of 0.512 (v)

When your DMM is in the resistance range the voltage difference between the probe tips it uses for the R measurement is normally much less than a Silicon diode's forward voltage drop of 0.6 - 0.7V so it can only show a high resistance (the diode cannot conduct due to lack of forward voltage). 
If your DMM has a separate diode test setting, the voltage difference between the measuring tips is about 2 - 2.5V so it can open most of the diodes (even red LEDs but not white or blue ones)  and the display shows directly the forward voltage of the diode under test at a certain (small) forward current like say 0.5 - 1mA, not more. This low current explains why your 1N4001 has  .512V forward voltage (threshold).

Of course you could check the open voltage difference between the tips of your DMM in either the resistance or diode test ranges by measuring the DC voltage by another DMM set in DC voltage range.

If the resistance range has several settings like 200 Ohm, 2kOhm, 200kOhm etc the voltage difference of the tips changes (increasing) accordingly so you can see different resistance values for the same diode but voltage difference still way under any forward voltage value.  This may not be so in case of older analog multimeters that were designed with higher output test voltages in their resistance range.

Bottom line is if you have the diode test setting in your DMM, then use it for diode or transistor B-E or C-B diode checkings but no much sense for using the resistance range for such tests.

rgds,  Gyula

[Mk1]

@jadaro

I don't have sufficient testing equipment , to determine that , but if you can get power out without effecting the efficiency of the original circuit , it may be a good way to go . It light led both direction because of the coil that go back and forth them self , and doesn't seam create any disadvantage to the pulsing circuit ,It may be easier on the transistor.

Mark

Edit also the coil has self inductance when done like that , witch doesn't seem to destroy the pole when powering something.