Joule Thief

[altrez]

@TheNOP

With my meter's I can not see it drawing anymore power. With that said can you point in the right direction to see that it really is pulling more power?

I have tried 3 different meters and had a friend come over and test with their meter as well. We simply can not find any extra power draw? We have even isolated it down to a source power supply and again it shows no extra power used?

Do you know of any different tests I might perform to show that it is in fact drawing more power with the toroid in place?

Thank you!

-Altrez

[TheNOP]

With my meter's I can not see it drawing anymore power. With that said can you point in the right direction to see that it really is pulling more power?

I have tried 3 different meters and had a friend come over and test with their meter as well. We simply can not find any extra power draw? We have even isolated it down to a source power supply and again it shows no extra power used?

Do you know of any different tests I might perform to show that it is in fact drawing more power with the toroid in place?

i already did tell you where you can have more infos on this.
http://en.wikipedia.org/wiki/Lenz%27s_law

if you make it so your secondary draw more current.
the light britness of the lamp will tell it to you.
you can use a normal transformer for testing this.
either short the secondary for a quick short period, be carefull if doing this, and check what the light does.
or use small values resistances able to support a lots of watts.

[jeanna]

@Altrez,
The part I am just not understanding is why you have the 120 volt electric power supply in your drawing.

What you say agrees with what I have seen, but I have used a 1.2 volt battery for my power source. Your pictures insist you are using the 120 volt ac from the wall.

Are you using the main power? or are you making a joule thief and using the ac from that?

==

xee2,
I just checked in from making a jtc in an altoids box. (I will show you all when I commit to a frame for it.)
I will need to study my notes to see why you say my results are not in agreement with yours. I thought they were!

First it is 3PM and I need some lunch! (altoids all gone!)

bbs,
jeanna

[altrez]

@jeanna

I am using 120 volt output from an inverter that I built into the wall plug that you see in the picture.

@TheNOP

I will give that a try..

-Altrez

[TheNOP]

@altrez

what you are saying about:

With my meter's I can not see it drawing anymore power

is half of the truth.

i screwed it up a bit here, sorry.

what i say is your statement, "draws no extra power form the source ", is not true.

is only true in 1 case.
but there are 2 cases that can happen.

you will have less currents on the lamp if the impedence of the coil is to go higher.

you will have more currents if the impedance of the coil was to go lower.

it is a simple resistances in series problem.
where one of the resistance is a coil impedance.

my main point is that the current will be affected with the way you are doing it.
there are no gain to be made that way.