Joule Thief

[resonanceman]

It looks like  MOTs are hard on  transistors

I have  blown 2 3055s in  2 days .

The  first one  to go  took me a while to figure it out .

Radio Shack  had a couple  5.1 V zeners   I hope that they are  big enough .....only 49mA
Anyone know  if they can be  used in parrallel ?




Who was it that was wondering  about  lighting  8ft floros ?
I got one

Once I  get  running again I will give it a try

gary

[jeanna]

@ Jeanna,
Carnt find it, musta left it in the bread thingie,    seriously though, I have lit a fluro tube with my Hazens1 JT, made it gloooo, but I don't hold the record for 5 hours, the battery is on charge right now, so I will hang a fluro on it tomorrow sometime.
jim

I wonder what makes the difference.

The one last night went for one full hour LESS maybe more, maybe only 4 hours instead of 5 1/4 hours!

I had 'fixed' the caps. Now, I am wondering about the blundering. Perhaps another fortuitous blunder.
If 25uF is better than 100uF, or if maybe the battery was not as fully charged. It was fully charged, and I cannot thnk it would make the difference of 23%.

So, I will use  10uF cap across the fully charged battery today and see. (I wish those variacs were not so very expensive... or maybe someone can help me use one from a radio. I have a take apart radio with a variac as tuner.)

Thanks jim

making headroads galore,

jeanna

[nievesoliveras]

@all

The transformer I was experimenting with, I could not get more than 9v from it.

I took it off and put in its place a ferrite bar with 3 feet of #26 wire folded in half and connected as a joule thief to the self charger which now has 1n4001 diodes with the same 104k ceramics.

Then I connected my old AAA camera battery that is damaged, it cannot hold the charge. I measured it and it had 0.46v. I connected it to the circuit and went to the grocery. When I left the led was off. When I came back it was on and the battery has 1.15v.

I connected a 47000uf 35v cap I had from a bedini project I did. The cap gets charged to 1.15v at the same time the led is lit and the battery is charged, but suddenly it discharges and gets to 0.0v and start slowly to fill up.

I tried to use it when it gets to 1.15-1.16v to see if the circuit could run with the cap only.  The cap keeps the circuit lit for a few seconds and then it turns off.

I connect the same battery again and everything returns as it was and the cap start filling again.

Any ideas on how to get the circuit that now is charging to work with the cap only?

Jesus

[Pirate88179]

@ Jim:

You have my sympathies mate.  Whenever our Govt. here does something like that, they make an exemption for all Govt. buildings and employees.  Our Govt. is out of control on a mad power grab so we are not too far behind you guys down there.  I agree with those here that say screw them and power it with a combination of free energy devices.  Wind, solar, EB, JT's, flywheels, etc.

@ Gary:

I was the one that asked about an 8 foot tube.  I'll bet the Fuji could light it.

Bill

[xee2]

@ jeanna

I made a quick test of the 3" toroid and it seems to be much the same as my 2" toroid. The output from the pickup coil is 137 volts but reversing the diode direction gives less than 2 volts. So output current is much greater in one direction than the other. I had no problem getting it to work. If you have another toroid I suggest you duplicate my coil and see what you get. It is a very simple coil to make. Just make all of the turns for each coil go around toroid in same direction. As you can see, there is nothing fancy about the winding job.

NOTE: All coils do not have to have turns going the same way, but all turns in each of the coils must go the same way. I hope that makes sense. Correct leads to connect is determined by trial and error.


Pickup coil output lights a neon bulb very brightly when it is put in place of the voltmeter.

PS - You do not need the 200 uF battery capacitor. It is in diagram becaues I had it there when I did the test. Also the output 60 pF capacitor can be most any value. The larger it is the higher the voltage will be.