Joule Thief

[gadgetmall]

Hi Gagdet once you've said that you're charging back the 1.5v battery with the Ucap. How do you do this? just plug the positive and the neg of the batt to the Ucap polarities?
Thanks

HI . They are hard to charge up and not a "normal capacitor . Think of them as trying to charge up a direct short . they will remain that way for days until they reach .5 volts at which time your led should light . I don't try to charge them from dead 0 . Hit them with a 6 or 12 volt battery for a second or two and get the volts up to .5 then they will take over. there is NOTHING an old cap charger can do for these . further more there is no energy in regular capacitors like battery caps . Ask anyone who own one. Bill even know this .
Mrmags i doubt your will get anything from IST . He has already threatened me in Pm's > i am simply waiting almost 2 month waiting for a dang shipping charge he ows for 60 pounds of electronic stuff and he really didn't know when to quit . His mess will sit here until the end of the month and then I'll put it in a storage bin and he will have to pay the storage fees plus shipping . I have been way too generous even taking my time and account to purchase these things for him being he could not do it himself for some strange reason . Anyways a friend he was and i was probably the only one he really had  but there you go . NEVER TRUST ANYONE > i should have know as My best friend for life ran off with My now Xwife  

Gadget

[MrMag]

Sorry to hear that Gadget. I know, it's really pretty sad. You try to help someone out and see what you get. I wouldn't say don't trust anyone. There are a lot of very good people here that I would trust. I just don't like it when you help someone out and then they start calling you names. That's bad karma. I think it's pretty funny now that he shows the generator in his pictures. I know I will never see it again, I just like to rub him a bit. If you get stuck with the parts, let me know. I'm just about ready to start playing again. Maybe I can work something out with you. Good luck!

[jeanna]

HI . They are hard to charge up and not a "normal capacitor . Think of them as trying to charge up a direct short . they will remain that way for days until they reach .5 volts at which time your led should light . I don't try to charge them from dead 0 . Hit them with a 6 or 12 volt battery for a second or two and get the volts up to .5 then they will take over. ....

I am so glad to hear this instruction.
Thank you. I am going to try it right now.

But what do you mean by

get the volts up to .5 then they will take over.

I think you mean I can now put this into the C-E spot with the diode and something might happen?
Thank you for  this information as I had not been able to make your circuit work.

jeanna

[Pirate88179]

MrMag:

I remember well you kind offer to loan me a scope.  That is what motivated me to look on Ebay which is where I found the one I have now. (Tectronics)  I will not forget your kind offer, and it is this type of cooperation amongst us that will help us move forward.

Thank you once again.

Bill

[jeanna]

Hi everybody,
I did a small test that took the last 3 days.

1--I used a circuit that produces 400-500v to run a LoA bulb and I let it run the battery down.
That took 6H20min for the photons to finally cease coming out of the bulb.
The end voltage in the battery was ~0.56v
I made a pic of it.

2--Then I used the exact same battery recharged in the exact cell of the recharger and repeated the test, this time using a string of  35 led christmas lights.
This took between 5h 45m   and 7h 20min to completely stop lighting.(I was watching a movie )
the end voltage in the battery was~0.62v

3--So, today, I ran this same test with nothing in the output.
I used the same exact battery recharged in the same cell of the recharger.
At 6h30min the battery reached 0.72v.

I didn't try to make a light start until later, but it is a good possibility that my theory is close to right about what actually takes all the power in a joule thief circuit.

The upshot is, do not use a more powerful transistor than you need to give your output volts, because it will just run down the battery unnecessarily.

thank you,

jeanna