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Overunity Machines Forum



Joule Thief

Started by Pirate88179, November 20, 2008, 03:07:58 AM

Previous topic - Next topic

0 Members and 163 Guests are viewing this topic.

resonanceman

Jesus

Thanks for posting your schematic.

I am not sure that I understand all of it.....but I think I got most of it down.

I am not sure why you have the "push to charge" switch where you have it.

Is the neon light just for overvoltage protection?
If so it might  be possible to replace it with another coil.
Another camera transformer or a JT wound for lightings CFLs might do.

I am thinking that if the output  of your trigger coil was hooked up to the secondary of a fairly high impedance coil ( in series ) the new coil will make the circuit higher impedance and probably add a little kick of its own.
The primary could  be hooked to a bridge and used for feedback.
Here is the tricky part... the voltage of the place  you connect the feddback to is important.
As long  as the spike in  your primary winding  is less voltage than  the voltage of the part of the circuit it is connected to the primary will have very little effect........once the voltage of the  spike goes over that voltage  most of the extra voltage will become feedback

In other words the spike will be clipped by the bridge.

gary

electricme

Thanks Jesus,

Here is the last section of the circuit.
I forgot to show the arrow pointer on the lower transistor, it should be to the left arm that goes to the diode on the Pos rail.

Have you found your 1.5 to 12 volt circuit and post it please.

jim
People who succeed with the impossible are mocked by those who say it cannot be done.

electricme

Jesus:

Here is another section on how I think you can "tap" into the high voltage section with another HI V transformer, just add another HV transformer into the Hi tension out put, you will need a transistor that can handle 5Kv or more, maybe a fly back transistor in a TV set, then feed the HV into the top of the transformer and take out the Lower voltage from the decondary and feed it back to the battery via a diode and the BD139.

Bothe the bases of the BD139 and the HV reansistor are connected together so they both turn on in sync, we might have to place a small electrolytic after the lo voltage diode coming out of the transformer so it can soak up any excess residude voltage and it can be dumped into the battery.

I see this working the same as if someone wanted to feed electrical energy from an aerial antenna and fed it into the tower of the ignition coil, andyou then take the energy out from the low tension or secondary section to charge up a battery.

This "may" be able to charge up a 12v car battery if it can raise 14 volts at 2-5 amps.
Wishful thinking ha ha.

jim
People who succeed with the impossible are mocked by those who say it cannot be done.

nievesoliveras

Quote from: resonanceman on April 03, 2011, 09:26:30 PM
Jesus

Thanks for posting your schematic.

I am not sure that I understand all of it.....but I think I got most of it down.

I am not sure why you have the "push to charge" switch where you have it.

Is the neon light just for overvoltage protection?
If so it might  be possible to replace it with another coil.
Another camera transformer or a JT wound for lightings CFLs might do.

I am thinking that if the output  of your trigger coil was hooked up to the secondary of a fairly high impedance coil ( in series ) the new coil will make the circuit higher impedance and probably add a little kick of its own.
The primary could  be hooked to a bridge and used for feedback.
Here is the tricky part... the voltage of the place  you connect the feddback to is important.
As long  as the spike in  your primary winding  is less voltage than  the voltage of the part of the circuit it is connected to the primary will have very little effect........once the voltage of the  spike goes over that voltage  most of the extra voltage will become feedback

In other words the spike will be clipped by the bridge.

gary

If the circuit you are refering to is the cfl original modified. The neon is suposed to act as the triger switch when it gets to its conducting voltage.

It is supposed to send a very high voltage to the input battery and recharge it.
The problem is that maybe it switch to fast or that it stay lit and the circuit stops.
When I am trying to reply now the text scrolls up and down crazily I dont know what is happening.

Jesus

electricme

Jesus:

I see what you mean, no, there is no push to charge switch in my circuit (hand drawn circuits) I think you are refering to the yellow diagram, no, in my drawing1st drawing above, there is 2 Green and 2 Blue dollops of marks, I forgot to say you can take the pulces from either of the BLUE or the GREEN points to feed to the switching transistors, you can take your pick to what works the best for you.
Sorry if I wasn't clear about that before.

jim
People who succeed with the impossible are mocked by those who say it cannot be done.