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Overunity Machines Forum



Feedback To Source

Started by nievesoliveras, December 21, 2008, 11:28:28 AM

Previous topic - Next topic

0 Members and 16 Guests are viewing this topic.

Mk1

@all

Any of you tried smoothing the bridge dc output with 2 caps and a resistor? The bridge output needs to be stabilized to work properly.
Sorry if i am out , i did not get a chance to read everything yet. :-[

nievesoliveras

Quote from: Mk1 on January 20, 2009, 03:34:35 PM
@all

Any of you tried smoothing the bridge dc output with 2 caps and a resistor? The bridge output needs to be stabilized to work properly.
Sorry if i am out , i did not get a chance to read everything yet. :-[

Welcome @mk1.
On the answer to @gadgetmall I posted this link:
http://www.overunity.com/index.php?topic=6362.msg146283#msg146283
It is something like your graphic here but without the resistor.
The connections are going to the 12v side, but if you take the positive from the rectifier and connected it to the 1.5v battery as feedback to the source, the motor stopped just right then and there.
When I finish the three tests I am doing. By the way the third is your toroid idea. I have not built it because of the wire price and my recent unemployment. But I will look for old transformers wire. Or just do it with #26 and #30 wire left from other experiments I did in the past.
I will then will test your ideas, @gadgetmall ideas, @spinner ideas and any other idea that can help us to get a true feedback to the source.

Jesus

Mk1

In my experiments on feed back the problem a got was the higher voltage by the feedback raised the operating voltage , and killed the output.
I think it needs to be brought down to 1.5v to be effective.

This is a really nice tread you got here!

gadgetmall

@ Jesus . The problem i had with My feedback circuit that you corrected the polarity was that it would stop the oscillation unless i put a pot in there to balance ot the feed back to the battery ..Its like the resistor idea of Mk1's only variable because all these joule thieivs are using different wire cores transistors . the best way i have found with all the variables is to use two pots  one on the bias and one on the feedback secondary . as far as the number of turns to get your 1.5 volt charging and running its got to be at least 2 volts higher and at least a few Ma's above the discharge rate . again Mk1 might know the answer . I know on my bedini piggy back coil is puts out 100's of volts until i feed it back to the battery then i read 15 volts on the cathode side of the large diode i use . and it always is about 2 and a half volts above the primary running battery . so i feed 100 plus in to 12volts and it equates to 2.5 volts over the battery and 20 ma over the draw of the system ..
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nievesoliveras

Quote from: Mk1 on January 20, 2009, 05:52:13 PM
In my experiments on feed back the problem a got was the higher voltage by the feedback raised the operating voltage , and killed the output.
I think it needs to be brought down to 1.5v to be effective.

This is a really nice tread you got here!

My circuit gives with the voltage divider.98v one way I think that 3.98v the other way. so the high voltage is no problem here.
I know that there is high voltage because the neon bulb lights very brilliant. But when I measure it gives the mentioned voltage.

Quote from: gadgetmall on January 20, 2009, 07:43:07 PM
@ Jesus . The problem i had with My feedback circuit that you corrected the polarity was that it would stop the oscillation unless i put a pot in there to balance ot the feed back to the battery ..Its like the resistor idea of Mk1's only variable because all these joule thieivs are using different wire cores transistors . the best way i have found with all the variables is to use two pots  one on the bias and one on the feedback secondary . as far as the number of turns to get your 1.5 volt charging and running its got to be at least 2 volts higher and at least a few Ma's above the discharge rate . again Mk1 might know the answer . I know on my bedini piggy back coil is puts out 100's of volts until i feed it back to the battery then i read 15 volts on the cathode side of the large diode i use . and it always is about 2 and a half volts above the primary running battery . so i feed 100 plus in to 12volts and it equates to 2.5 volts over the battery and 20 ma over the draw of the system ..

That sounds interesting. I noticed that when the battery I connect is of some voltage also happens the same you are explaining. It has happened to me too. Just the motor used to stop.

@all
I will post the results I have for the people that are following the thread and finish the experiments with the transformers or joule thiefs. I will test also your ideas and I will post my results.

I do not have fancy equipment. I only have a digital meter and an analog meter, also a strong desire to succeed.

Jesus