water "polarization", INSTEAD of water electrolysis?

[sm0ky2]

I

But what is now really interesting is, that one cup now has way too much H Atoms inside and the other one, way too much O atoms... Although they are both now electrically neutral (after the discharge)
This would actually mean, that e.g, if you take again the cup with the too much H atoms in it, and pour it again in the Generator, then in the resulting new positive cup will be even more H atoms. Like that it should be possible to get such high H concentrations, that the H will start to gas out of the water and you will have H2 leaving the water -> Hydrogen.
And the energy to generate the Hydrogen did come from the Autoprotolysis (heat, through molecular movement) and not from the gravitational energy.
This should actually violate the 2nd LOT.

these 2 waters could be ran through opposite sides of a membrane fuel-cell, and the resulting electricity added directly to the energy that was 'discharged'.

[drspark]

the re-neutralized water is then returned to the Charge seperator Cell in circles.
ResinRat2 where are you 

[Shanti]

Do you have a link to the video its been year or two?

http://video.google.com/videoplay?docid=-3539465122468328116#25m24s (at 25:24)

Maybe two membranes in the water as a dielectric and just a strong charge across it will separate the water. If its PH is 7 when you start.
Sandwich:
I=insulator.
C=conductor.
w=water.
M=membrane???
+CIwwwMwwwwwwwwwwMwwwIC-
The wider the cell, the higher the needed dc voltage charge across it. BUT its just a charge not a current flow.

Can it be done with only one membrane in the middle?
+CIwwwwwwMwwwwwwIC-

Yes it can be done that way, there's also a patent for this, well not exactly. The patent is without the membrane, but you got me...(shouldn't make a difference)
The problem are the insulators. As the insulators have a much higher resistivity as the water, almost all the voltage potential drops at the insulators and will not be seen by the water anymore. See it as a conventional series resistors combination. The voltage drops across the different resistors is proportional to their relative resistance...
This means, you have to develop really huge voltages to split water like that...

The wider the cell, the higher the needed dc voltage charge across it. BUT its just a charge not a current flow.

Well that's not really correct. This is the same as Stan Meyer who always proclaimed he's just using voltage but no current, but you can't charge a capacitor without current!!!
And if the water breaks up inside this capacitor, which you suggested, then this means, the properties of your dielectric changes, as the ions will now wander in the E-Field of the cap and therefore weaken it, which on the other hand means, the charge of your capacitor will drop. And if you would want to keep the charge, you would have to put more current into it.
Sure this as you also already suggested could be counteracted by using the lower density of the gases to perform the work, of getting the charges out of the "dielectric" of the capacitor. But as my calculations have shown, the density difference should be way too low to counteract the the energy needed to get them out. But my calculations are always very rough, and certainly not all factors included. So maybe...

[drspark]

Shanti,

I wasn't trying to produce gas with that charged cell, only separate the lo from high PH waters.
Once separated the two spaces near to the plate on each side is drained into two separate containers. Hoping the membrane will maintain the separation as the two drain.

Yes to charge the cap you have a current flow and as the water *separates* there will be a current. But is nothing like Current used in brute force electrolysis. and electricity never touches the water, in this stage.

[drspark]

Shanti,

In the case of two membranes only the water on the side closest to the plate is drained on each side and the water in the middle in discarded.
the I=insulator is the container wall  think of a rectangular container with the conductive plates on the outside.