One wire transmission: Tesla and Avramenko

[jadaro2600]

Also, all along I have taken the stance that the JT is not OU or even a free energy device by itself.  I do strongly believe that when used correctly, and in connection with other devices, free energy can be obtained. One example is the JT running off of my earth battery (which I have yet to do due to the winter here) and seeing if it can light a 48" long tube.  If so, I would be effectively lighting that tube for free just like I have been able to light leds for free from it last year.

I tried making an earth battery, the soil is just too neutral around here.  I used a brass rod and a steel rod - not zinc.  THere was very little voltage between th two of them placed three inches apart.  IF you call that an earth battery.

Otherwise, employing antennas to earthen grounds doesn't really classify as an earth battery, it would be more like an earth ground with a tank circuit ( a radio ).

[Pirate88179]

@ Jadaro:

Well, there are many things one has to do to maximize the output from an electrode style earth battery.  first, you need the right materials, and the more of them (mass) the better.  I used carbon rods (1" dia x 18" long) and magnesium blocks. (three fire starter blocks about 3" x 1.5" x 1/2" thick ea. then banded together)  Then, the greater the distance between your electrodes the better.  I am using about 4.5 feet as that is all the space I have here.  Then, you have to align the electrodes along the north/south meridian (NOT magnetic north, there is a difference) placing the positive electrode to the north side. (In my case that is the carbon)  Also, you have to look up the magnetic dip angle for your area.  This information would be available from the same place you find your magnetic declination number)  You want the angle from the bottom of the + electrode to the - electrode to match the dip angle as close as possible.  The soil does not matter all that much.  Some people say  it is just the water in the ground acting as an electrolyte, but my output number go up when the soil is dry.

Last year I got 2.2 vdc and up to 426 mA's.    If you are interested, just google "telluric currents" of the earth.  This is where the energy comes from.   Interesting stuff.

Bill

[DrStiffler]

@ Jadaro:

Well, there are many things one has to do to maximize the output from an electrode style earth battery.  first, you need the right materials, and the more of them (mass) the better.  I used carbon rods (1" dia x 18" long) and magnesium blocks. (three fire starter blocks about 3" x 1.5" x 1/2" thick ea. then banded together)  Then, the greater the distance between your electrodes the better.  I am using about 4.5 feet as that is all the space I have here.  Then, you have to align the electrodes along the north/south meridian (NOT magnetic north, there is a difference) placing the positive electrode to the north side. (In my case that is the carbon)  Also, you have to look up the magnetic dip angle for your area.  This information would be available from the same place you find your magnetic declination number)  You want the angle from the bottom of the + electrode to the - electrode to match the dip angle as close as possible.  The soil does not matter all that much.  Some people say  it is just the water in the ground acting as an electrolyte, but my output number go up when the soil is dry.

Last year I got 2.2 vdc and up to 426 mA's.    If you are interested, just google "telluric currents" of the earth.  This is where the energy comes from.   Interesting stuff.

Bill

@Bill

So is this correct ( 2.2 * 0.426 = 0.9372 ). Now if you did this for 1 second that is 0.9372 Joule/Seconds or Watt/Seconds which ever you prefer. Now this is very small unless you can do it for 3600 seconds and at that point you would have 0.94WHr, pretty damn good. You always need to include the time in the equation otherwise it can be fooling in the least. Say you get 1000J for only one second, wow a 1000W/sec, but that only applies if you can sustain this for longer than a second. So 1000W/sec / 3600 = 0.2778 or 0.2778 WHrs. The details are in the time

If you are getting 426mA constantly, I will book a flight to see it as this would be something.

DrS.

[Pirate88179]

@ Dr. Stiffler:

Good point.  Since the meter on mA's is kind of like a dead short, yes, the numbers go down when just checking mA's.  I have not timed how long this takes, but from memory (not a very good scientific observation) it was like....426.....425....424....423.... dropping very regular at about one number/second.  But, as I said, I only did this to check for the power at that moment.  I am sure if I left it connected long enough, it might go to 0. (probably)  But now I am working with the joule thief circuits and supercaps so, I hope to light a 48" tube (or more) from this set-up.

How is your work going?  I noticed that you have not posted much here on your topic lately. (I don't really blame you)  I have read feedback from others there that your work is going well and you are close to publishing.  Congratulations.

If you get a chance, check out our joule thief topic.  It is unusual as there is hardly any "internet forum" BS going on there.  Just a lot of good folks trying different things and sharing the information.  I have learned a lot since starting that topic.  It is not ou but I still think some amazing things have been done with a single AA battery.  Best of luck and success to you in your work and publication thereof.  Thanks.

BIll

[sparks]

   If for every milli amp milli second you have a voltage multiplier circuit that raises the voltage on a variable capacitor 20volts.  At the end of 1 second your capacitor would be up to 20,000 volts.  After 2 seconds 40,000 volts.  After a minute 1.2 million volts.  Now short that capacitor out in say a millisecond. 
Amperage in your circuit will be I=E/r  Since your resistance is as close to zero as you can get it say .1 ohms.  Amperage is now going to be 1.2million volts/.1 or in a miilisecond you are going to get a flow of 10.2 million amps.  This was from a flow of 1 milliamp for 1 minute into your system.  Lets break that 10.2 million amps for one millisecond down compared to your investment amperage.  Input  1 milliamp minutes  Output 170 milliamp minutes.   There is a gain of 169 milliamps per minute or in one hour you have some extra work of about 10.14 amp hours.  If your 10.2million for a millisecond discharge is invested in some reactive energy system that allows this discharge to oscillate for an hour  instead of just flowing for 1 millisecond you can see that your voltage multiplier circuit coupled to the proper capacitor and resonant circuit can get very powerful very quickly.  10.2 million amps flowing in a resonant circuit for an hour is sure to let the near field get excited more than lighting up an incandescent bulb with the same investment wattage.