ENERGY AMPLIFICATION

[Magluvin]

The problem is that "energy is neither created nor destroyed" -- is usually misapplied, as well as "the total energy of an isolated system remains constant."

If we charge a 100uf cap to 100v and connect it to a 100uf cap with 0v we end up with 50v in each cap, we lose 50% of the total energy that was in the first cap to start. Calculate the energy total in 2 100uf caps at 50v each. Where did the energy go?
Mags

[lancaIV]

If we charge a 100uf cap to 100v and connect it to a 100uf cap with 0v we end up with 50v in each cap, we lose 50% of the total energy that was in the first cap to start. Calculate the energy total in 2 100uf caps at 50v each. Where did the energy go?
Mags

From capacitor/caps to cups :

You have two cups  in front,not caps  ,one full with water and the other empty !
Now you fill the second = empty cup half-full by the full cup with water !


Now you have two halffull, or one halfempty and an other halffull cups :


I do not think that somebody has to explain where the water from the first cup became lost !?
100% same water content,in two cups now as 100% capacitance in Joule/Farad in 2 capacitors now !

[XR IX]

If we charge a 100uf cap to 100v and connect it to a 100uf cap with 0v we end up with 50v in each cap, we lose 50% of the total energy that was in the first cap to start. Calculate the energy total in 2 100uf caps at 50v each. Where did the energy go?
Mags

Not sure what your expectation is here, if you take a full glass of water, and pour half of it in another empty glass now you have two half filled glasses. However if you raise the ambient potential of the first glass above it's equal potential... like a higher position, you can siphon all the water from one glass to another.

This is a classic problem with OU, we don't consider the "outside" and we don't integrate it with more water.

Consider this idea with capacitors, you have two plates separated by a dialectic. In this model however, the lower plate is attached to a mover, like a motor, so the plate can spin. Charge the plates, and you have difference in potential, now disconnect the upper plate so those charges wont move on the upper plate,  and place both plates in a magnetic field. Spin the lower plate, if you place an AV plug on the plate you should be able direct the movement through a load, back to ground. If you don't think this is possible, stick a tube in a pool fill it with water and spin the tube over your head. It creates that siphon effect. You push charges off with the mover, and the capacitor draws the charges back because the plates maintains an equal charge level between the upper plate that is stationary and the flow being generated by the mover on the lower plate.

It is a charge pump, with the limit of the Farads of the capacitor.

[NickZ]

   Besides the limit of the capacitor, can you show just how any of this can produce OU? Or is it still less than OU?   Emptying the glasses requires additional energy. As well as raising the first glass higher than the second one.   So, still less than OU, when calculating the losses. Or not? Can you show a video of how you think that there is any actual gain.   NickZ

[AlienGrey]

   Besides the limit of the capacitor, can you show just how any of this can produce OU? Or is it still less than OU?   Emptying the glasses requires additional energy. As well as raising the first glass higher than the second one.   So, still less than OU, when calculating the losses. Or not? Can you show a video of how you think that there is any actual gain.   NickZ

Ha , Ha, in a stable world what you say is so, but what happens if we tip the ballanc a bit supose i freez the water then i end up with more why because it expands.

Now how can we do that with electricity ? well what is electricity ? is it an electron or a magnetic component of existance and then there is the wire, so what quality has the wire got and how could we alter it if thats the problem but is it?

AB