ENERGY AMPLIFICATION

[forest]

keep lips 

[forest]

I'm not sure how to understand coil polarization during disconnection. Assume we have charged coil from DC source of high current then we disconnect + from battery to coil and coil energy collapse. We know that coil tries to maintain current flow and become a source. What is the polarity of coil-source then ? Is that the same a battery so we have + on disconnected coil end and - on the other ?

[gyulasun]

I'm not sure how to understand coil polarization during disconnection. Assume we have charged coil from DC source of high current then we disconnect + from battery to coil and coil energy collapse. We know that coil tries to maintain current flow and become a source. What is the polarity of coil-source then ? Is that the same a battery so we have + on disconnected coil end and - on the other ?

hi,

I think you have to consider voltage across the coil and current in the coil.

Voltage polarity flips across the coil after the moment of switching off the battery voltage.

Current polarity does not change, only it starts decreasing from its earlier value towards zero, depending on the load across the coil.
IF there is no load and the coil is left on its own, the energy in the coil starts swinging as in a LC tank circuit (the C is the coil's self capacitance) until losses dissipate all energy.

Gyula

[forest]

hi,

I think you have to consider voltage across the coil and current in the coil.

Voltage polarity flips across the coil after the moment of switching off the battery voltage.

Current polarity does not change, only it starts decreasing from its earlier value towards zero, depending on the load across the coil.
IF there is no load and the coil is left on its own, the energy in the coil starts swinging as in a LC tank circuit (the C is the coil's self capacitance) until losses dissipate all energy.

Gyula

Thank you.
I'm not sure if I understood but if I connect coil to DC battery, charge it with current then disconnect coil squeeze trapped electrons and become source of voltage in opposite orientation then battery yet electrons flow in the same direction but slowing due to difference in potential across coils ?
Then if we immediately connect coil back to source battery what would happen ?

Could it be that coil having higher voltage then battery would recharge battery back (minus some lost energy during disconnection time )  ? Maybe we should place a diode which will redirect trapped electrons from - side of coil back to - terminal of battery ? Hmm ..or from + side of coil ? Anyway we really do not need those electrons, let them return back to source.

I'm wondering if Tito would be so nice to help here.We have two choices:
1. Somehow return back electrons from coil to the source battery
2. Let them stuck inside coil so the next time coil is shorted it won't take much of them from battery

hmm..Tito place your bet ... 1 or 2

[forest]

I don't know if we can trust in circuit simulation programs. 

Check this simple circuit. It shows that when coil is disconnected it become the source of energy and electrons try to escape from it.If we place zener diode it sees higher voltage then a battery source and open.
IMHO it should be just a spike coming from coil to the battery but simulation shows that zener diode is open for a long long time and remain open at then end of current flow.Simulation also shows that curren flow still from battery through the open zener diode to the coil and not from coil.That's strange indedd if coil is a source of higher voltage then battery.
Personally I would throw away simulations