Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



ENERGY AMPLIFICATION

Started by Tito L. Oracion, February 06, 2009, 01:45:08 AM

Previous topic - Next topic

0 Members and 14 Guests are viewing this topic.

Dave45

Quote from: d3x0r on December 07, 2014, 09:16:24 AM
from either view the current remains the same and doesn't reverse.  The collapse of the field maintains the forward inertia... the build of the field is what prevents the flow in the first place.  The field collapse is what makes it work as a filter so well, because the current is mainted forward as it's allowed to collapse... if it spontaneously reversed then chokes would not work to filter noise, they would amplify the noise.


a voltage gradient is present, a current starts, a field builds, the current gets to it's max... when the current stops the field collapses and squeezes out the last bit of current the same direction that it got when the filed first started to build.  Until the field is entirely collapsed the current cannot reverse.


unless you change your notation in the middle and talk about conventional current and electron current in the same breath there is no reversal of either paradigm itself; only when changing from one view to the other at whim.

I agree  :)

But what is not realized is current is a product of electron flow, current is not a product of the battery.
http://www.learnabout-electronics.org/PSU/psu31.php
The sim on this page explains it well, when the switch is on current flows through the inductor and load and into the battery, when the switch is off current circulates through the diode.
If current were a product of the battery it would not take the path through the diode but go directly to the neg terminal of the battery.
In order to understand why this happens you have to look at the circuit from an electron flow perspective then you see the electrons moving from neg to pos are cut off when the switch turns off and the electron takes the path through the diode, the electron is not attracted to ground so continues to circulate through the load , inductor and diode.
And as a result of electron flow current continues to circulate through the network, this simple circuit shows that current is a product of electron flow and not the battery.

What is interesting is that the electron is neg but the resulting current is pos.


Dave45

Quote from: Dave45 on December 07, 2014, 09:59:11 AM
I agree  :)

But what is not realized is current is a product of electron flow, current is not a product of the battery.
http://www.learnabout-electronics.org/PSU/psu31.php
The sim on this page explains it well, when the switch is on current flows through the inductor and load and into the battery, when the switch is off current circulates through the diode.
If current were a product of the battery it would not take the path through the diode but go directly to the neg terminal of the battery.
In order to understand why this happens you have to look at the circuit from an electron flow perspective then you see the electrons moving from neg to pos are cut off when the switch turns off and the electron takes the path through the diode, the electron is not attracted to ground so continues to circulate through the load , inductor and diode.
And as a result of electron flow current continues to circulate through the network, this simple circuit shows that current is a product of electron flow and not the battery.

What is interesting is that the electron is neg but the resulting current is pos.

Looking at the circuit using this logic this is the reaction of this circuit.
http://cdn.makeagif.com/media/3-30-2014/X93gwp.gif
The black represents electron flow, the red represents the resulting current flow.

MarkE

Quote from: Dave45 on December 07, 2014, 09:59:11 AM
I agree  :)

But what is not realized is current is a product of electron flow, current is not a product of the battery.
http://www.learnabout-electronics.org/PSU/psu31.php
The sim on this page explains it well, when the switch is on current flows through the inductor and load and into the battery, when the switch is off current circulates through the diode.
If current were a product of the battery it would not take the path through the diode but go directly to the neg terminal of the battery.
In order to understand why this happens you have to look at the circuit from an electron flow perspective then you see the electrons moving from neg to pos are cut off when the switch turns off and the electron takes the path through the diode, the electron is not attracted to ground so continues to circulate through the load , inductor and diode.
And as a result of electron flow current continues to circulate through the network, this simple circuit shows that current is a product of electron flow and not the battery.

What is interesting is that the electron is neg but the resulting current is pos.
Dave, think of an inductor as a flywheel:  As the flywheel resists changes in speed, an inductor resists changes in current flow.  The battery is a needed source of EMF in order to establish a current flow in the inductor.  Once the current is established, the inductor resists increasing or decreasing that current.   As the transistor turns off reducing the current through it, the inductor BEMF causes the voltage on the switched side of the inductor to swing away from the battery voltage that is on the other side of the transistor.  The voltage keeps moving until the diode passes the balance of the inductor current no longer being carried by the transistor.  The now reverse voltage across the inductor acts to reduce the current.  When the transistor turns back on, the coil again resists changes in current, and the current only increases at a rate proportional to the voltage difference across the inductor:  battery voltage to load voltage.

d3x0r

Quote from: Dave45 on December 07, 2014, 09:59:11 AM
I agree  :)

But what is not realized is current is a product of electron flow, current is not a product of the battery.
http://www.learnabout-electronics.org/PSU/psu31.php
The sim on this page explains it well, when the switch is on current flows through the inductor and load and into the battery, when the switch is off current circulates through the diode.

and the arrow that is drawn, in both pictures and the flow indicator in the animation the switch closed and switch open,  the current in the coil is the same direction. with no reversal