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Overunity Machines Forum



ENERGY AMPLIFICATION

Started by Tito L. Oracion, February 06, 2009, 01:45:08 AM

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0 Members and 12 Guests are viewing this topic.

nelsonrochaa

Quote from: padova on May 29, 2015, 08:20:05 AM
Ok, that has to be respected, about someones work. I watched videos more carefully , just can't see
how you connect a Transformer in exciter circuit, and another coil. Anyway, I was just  curious , also
watching some presentations, one can get his own ideas :)
I'm working on some my things, and it takes time to be finished, although not so complicated, just need work.

thanks

Padova ,

Thanks for understand the situation ,
about you thinking that is complicated is not, the circuit  work similar like a joule thief . the problem is find the right values to circuit "swing" in harmony  and achieve resonance .  I see people make heavy coils  but for what ?
If don't understand how to tune with a smaller coils ....  If you pay attention in the scope you can see that wave are not deformed , and look to the values RMS and AVG . Just a single value modification in the tank circuit will modify the values of oscillation and the output values . Need to have harmony in the values of all components. :) For that need to test with experimentation  , or rule bye the maths expressions to find the correct values .

Good luck for your tests



In this circuit that i show in my last video only use a npn transistor and couple of caps diodes and coils nothing more .
The circuit in the video is only a small demo for study all the aspects. We need to start by the floor not by the roof :)
 

TinselKoala

Quote from: nelsonrochaa on May 29, 2015, 06:41:36 AM
Hi ,

Answer your question:

If you use 10 caps of 1000uf  of 10v in series you will need to divide the capacitance for the number of caps.
1000uf /10 =100uf 


To operate to high voltage you say that need to have more caps why ? Have you some special reason ?


thanks

Yes, that's the special case for all caps of the same value. But in general, capacitors in series use the same formula as resistors in parallel, that is

Cfinal = 1/(1/C1 + 1/C2 + ... + 1/Cn)

The voltage handling simply adds up the voltage ratings of all the individual caps.

Magluvin

Quote from: TinselKoala on May 29, 2015, 11:42:39 AM
Yes, that's the special case for all caps of the same value. But in general, capacitors in series use the same formula as resistors in parallel, that is

Cfinal = 1/(1/C1 + 1/C2 + ... + 1/Cn)

The voltage handling simply adds up the voltage ratings of all the individual caps.

Here is where Im kinda having issues with this.

By definition  2 plates, 1 mile square each, 1 inch apart, at 1v is 1 farad..     Why the need for the 1v in that definition? ;) At 2v is the capacitance greater? well it should be being that the 1 sq mile cap is holding more energy than the previous definition.


I know batts and caps are not the same really, but lets say I have 2 electric bikes. 1 is 12v and 1 is 48v.  On the 12v bike I have 4 12ah sla batts in parallel which is rated at about 1kw. The 48v system has the 4 batts in series, which is also about 1kw. So whether I charge the 4 batts in parallel or charge them in series at 48v, their capacity total is the same.  Now, say we were to try and charge the 4 batts in series with 12v, as compared to charging the 4 batts in parallel with 12v, we have a big problem getting the 4 series batts to have as much stored energy as the ones in parallel.

In a simple circuit, say there is 5v across a 10uf 10vcap. Now if we wanted to change that cap to 5uf by taking 2 of those 10uf 10v caps and put them in series, we would only have 2.5v across each cap. So now we have less energy stored in each of those caps due to the series condition and only 5v across the whole. Mostly we never see caps in series in common circuitry. but the capacitance division is explained to us this way, never in a way that shows a comparison of 1 10uf 10v cap with 5v across and 2 10uf 10v caps in series with 10v across the whole, which is 5v across each cap.



Mags


gyulasun

Quote from: Magluvin on May 29, 2015, 12:50:57 PM

...
By definition  2 plates, 1 mile square each, 1 inch apart, at 1v is 1 farad..     Why the need for the 1v in that definition? ;) At 2v is the capacitance greater? well it should be being that the 1 sq mile cap is holding more energy than the previous definition.

...

Hi Mags,

I understand as follows: for a plate capacitor the capacitance is (Eps*A)/d  and if you connect such plate caps in series, then you simply increase d (distance between the plates) so the result is a decreased value capacitor. Voltage is not involved in this explanation.

Gyula

nelsonrochaa

Quote from: Magluvin on May 29, 2015, 12:50:57 PM
Here is where Im kinda having issues with this.

By definition  2 plates, 1 mile square each, 1 inch apart, at 1v is 1 farad..     Why the need for the 1v in that definition? ;) At 2v is the capacitance greater? well it should be being that the 1 sq mile cap is holding more energy than the previous definition.


I know batts and caps are not the same really, but lets say I have 2 electric bikes. 1 is 12v and 1 is 48v.  On the 12v bike I have 4 12ah sla batts in parallel which is rated at about 1kw. The 48v system has the 4 batts in series, which is also about 1kw. So whether I charge the 4 batts in parallel or charge them in series at 48v, their capacity total is the same.  Now, say we were to try and charge the 4 batts in series with 12v, as compared to charging the 4 batts in parallel with 12v, we have a big problem getting the 4 series batts to have as much stored energy as the ones in parallel.

In a simple circuit, say there is 5v across a 10uf 10vcap. Now if we wanted to change that cap to 5uf by taking 2 of those 10uf 10v caps and put them in series, we would only have 2.5v across each cap. So now we have less energy stored in each of those caps due to the series condition and only 5v across the whole. Mostly we never see caps in series in common circuitry. but the capacitance division is explained to us this way, never in a way that shows a comparison of 1 10uf 10v cap with 5v across and 2 10uf 10v caps in series with 10v across the whole, which is 5v across each cap.



Mags

Hi Magluvin ,
i Think  i understand what you try explain but are not things comparable . The battery convert or storage by a chemical way , the capacitors storage electrostatic charges so i think is not comparable .
About  the 4 batteries in parallel of 12a 12v you only have approximate 500Watt without considering other factors.
Now , are you talk about about Ah or effective power discharge drive by special C factor discharge battery ?
Are things very different because the capacity is not equal to the power discharge in that circumstances.