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Overunity Machines Forum



First electrical power output from a Pyramid

Started by hartiberlin, January 18, 2006, 05:32:45 PM

Previous topic - Next topic

0 Members and 8 Guests are viewing this topic.

Tigrotto

Hi everybody,
I just posted here the electric circuit I think would be .
Please, could someone answer to my question : Where to connect point E, please?

Tigrotto

Hi everyboby,
In order to not have misunderstandings on V6 description::
Like many of our friends here, I'm a scientist (physicist) and I understood well what is understandable !
1. But, due to the fact that there are some details "out of common scientific logic", this is why I preffered to ask those of us that knows this maybe directly from Thomas.
this is why I drawed the electrical circuit and this is why I asked you kindly : Where to go from E-POINT?
2. Thoms said here many times asking for our patience. In the same time he posted the V6 .
I don't want to waste time if this time can be recovered, this is why I'll try these days to replicate the V6.
In order to do this  I need to know :
A. Is this circuit correct what i posted here?
B. Where comes E-POINT : At A,B,C or D???
Pretty simply questions askink no more than a few words if one knows precisely the answer, otherwise, patience.
If I'm the only one asking these two details doesn't mean I'm the only one working here. I repeat, maybe from a non-scientific point of view the things are easier to understand!
We are here to help us together. And I ask you very kindly your help.
As me, maybe others os us are trying now to replicate .
Thomas himself invited us to "transparence" , following his example.
If Thomas himself will find ten seconds to answer these questions,will be great.
I'm sure these answers are the among others answer too .However, he's the "first voice" in this Orchestra.
Thanks in advance,
Ovidiu

Koen1

Well I do agree that the description of where exactly E connects to could be clearer.

But what I find more interesting is that it appears to be a fairly simple galvanic stack, like Stefan already remarked, which oscillates the building charges.
If however it were merely a case of oscillating charges that are tapped by using the coils, one would expect a form of ac or pulsed dc, but apparently the output is dc with an occasional ac spike...
Besides that, it is claimed the magnet is necessary for the circuit to work... Which is a bit odd...

Another matter of interest is the granite/quartz connection... Is is necessary to have quartz and/or granite in the pyramid base? If so, and if it needs to be granite, then what role does it play?
And why the copper tubing?

I do not find the "new" descriptions any more revealing than the previous guesstimated circuit.

mr. Trawoeger, can you please give clarity on these subjects?

starcruiser

Quote from: Tigrotto on November 21, 2007, 07:50:10 AM
Hi everybody,
I just posted here the electric circuit I think would be .
Please, could someone answer to my question : Where to connect point E, please?


It appears that your second capacitor is wired incorrectly, the output is taken across the second capacitor. The hot side comes from the collector (hanging in the pyramid) and the ground is from the frame of the pyramid. "E" goes to "A" from what I can tell.

It appears that the 2 additional wires are for measurements. Hope this provides a bit of clarity.
Regards,

Carl

Thomas_Trawoeger

@tigrotto: Sorry, i can?t follow your problem. Your schematic is pretty nice, but where?s the problem to fix connector E?
Do you wait for the well roasted Birds flying into your open mouth?

There is only one possible point for Connection E. Try it, and you will see, I am right.

Better idea: Wait for the whole Community if we built the Pyramide together. You don?t waste time, because we have plenty of it.
(You can?t earn any honour, because there are running some pyramides in different areas <if it?s true, but i hope so>)

I will give answers to the right time for everybody at the same time.

@Koen1: Pleas read the Thread carefully. The most important things are written above.

lg, Tom