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Overunity Machines Forum



Thane Heins Perepiteia Replications

Started by hartiberlin, May 28, 2009, 05:54:52 PM

Previous topic - Next topic

0 Members and 9 Guests are viewing this topic.

hoptoad

Quote from: baroutologos on June 11, 2009, 09:11:31 AM
I am with mr T. regarding voltage and magnet possitioning, although i do not agree fully. I have some experience with same pollar generators (as my current setup is) and they create a full sine wave of less amptitude than alternating pole setup. (Note that between magnets, no matter what the spacing is there is a scallar opposite pole of less power)

Anyway, at TDC voltage is not zero.

Could not be zero.
If voltage was zero then Peripeteia (as well as many other devices) could never work, since impedance has choked current and afterwards, no voltage exists to push electrons in the desired direction.

So following this reasoning we can conclude safely there is voltage at TDC.

Regards,
Baroutologos
Zero is not the same as nought. In AC it is the relative point between negative and positive voltage vectors, the sum of which is zero volts.

I'll stick with Faraday   LOL  ..... oh and I_ron   :D   Cheers

i_ron

Quote from: hoptoad on June 11, 2009, 09:56:25 AM
Zero is not the same as nought. In AC it is the relative point between negative and positive voltage vectors, the sum of which is zero volts.

I'll stick with Faraday   LOL  ..... oh and I_ron   :D   Cheers

I am aghast!!! Such confusion over over such a basic fact of life.

And so simple to prove. Take one magnet and one coil with a core (bolt, nails, laminations, what ever...) con nect your old ana log volt meter to the coil, OK

Now take the magnet and sit it on top of the coil. Maximum flux through the coil, right?  Zero volts (and zero am ps,lol) on the meter.

Now pick the magnet off and watch the meter as your approach the coil... the meter will swing up (with the right pole) and as you go over TDC will reverse direction and as you recede with the magnet will try to swing down.

As in the answer to #7..."A rotor lined up with the stator poles would result in maximum flux (φ) through those poles, but not maximum rate-of-flux-change over time ([(dφ)/dt])."

the maximum induced voltage and polarity,has to do with speed and direction of flux change.

Now just go and do the experiment and think about what you see...

Thanks Hoptoad!

Ron


Pageygeeza

Now I really didn't expect this from such a simple question. lol

I'm inclined to agree with i_Ron anyway.  Taking things to their most simplistic levels, it make more logical sense.  The way I look at is like this:  A coil of wire doesn't have a magnetic flux until power is applied, so to use it in a generator it is inert.  So to pass a north facing magnet across it from one side the current will flow all the way around in one direction, as the magnet hits the center it's not passing over any wire, so nothing is created.  Then it moves across the other side, as it moves away thus making the current flow in the opposite direction. 

Ramming clever sounding words into the mix just confuses things.  Personally, I think this is probably the most simplistic way of looking at it.

Just my 2 pennies worth. ;)

TinselKoala

"The induced electromotive force or EMF in any closed circuit is equal to the time rate of change of the magnetic flux through the circuit."

So if the time rate of change of the flux is zero, the induced voltage is zero.
And at TDC of a magnetic piston, the magnet is not moving, therefore the time rate of change of its flux in the wire (or coil) is zero. Therefore the induced voltage is zero.

This is Faraday's law of induction, perhaps the oldest EXPERIMENTALLY VERIFIED law of electromagnetism there is.

It is also the third of Maxwell's Equations: the Faraday-Maxwell Equation, which states that the curl of E is equal to the negative time rate of change of the B field.



petersone

Hi Pageygeeza
I thing I have to agree with you,anything going in one direction,then going in the opposite direction,must,at some point,between the two states, be stationary,unless I am missing something.
peter