Claimed OU circuit of Rosemary Ainslie

[Rosemary Ainslie]

Hi Paul.  Actually it's not quite that easy to caculate the output from the supply.  The point is that some energy seems to be either stored or regenerated from the supply.  You need a dc coupling to determine this - and at the frequencies required - and with the complexities of the waveform - it really needs to be fairly carefully established.

But Poynt has some pointers here.  Perhaps he'll oblige and explain his system.

Do I take it you're up for testing?  That would be just so nice. 

[Rosemary Ainslie]

Hi MileHigh.  I feel it's grossly inappropriate to indulge in shameless flirting through the aethernet.    To which end I was obliged to withdraw some comments I made.

Rosie. 

I can't comment on the rest of your post because - frankly - it's too highbrow for me.  But I was largely encouraged by your recommendation that  COP > 1 be explored.  So nice MH. I'm almost inclined to think that you're keeping an open mind.

But it's Saturday Night and here I am - in front of the computer.  Clearly I need to get a life.  Perhaps you can give us a link to some decent entertainment MH.  It would be much appreciated.  In any event this thread is regressing into something way too earnest to be taken seriously.  It needs some light relief.

[PaulLowrance]

Do I take it you're up for testing?  That would be just so nice.

Again, first I would need to know if you have replicated your own claim.

Paul

[Rosemary Ainslie]

Sorry Paul.  Yes indeed.  We replicated the test over and over.  All kinds of tests.  All gave extraordinary COP results.  I've now stopped all testing - mainly because my own representations here seemed to bear no fruit.  I feel the whole exercise is better dealt with by open source.  Not only the talent to do the required but also the interest. 

The replications included the accreditations by those companies.  They included BP, SASOL, ABB and Spescom - among others.  It made no difference to the advancement of the knowledge. 

[PaulLowrance]

Hi,

Just curious, am I missing something about measuring input power from the battery? According to conventional physics, the amount of power produced by the battery is the batteries _internal_ DC voltage * DC current.

The internal voltage is determined after the battery has been sitting unloaded for awhile. Measuring the DC current is done by means of a simple low pass filter.

But I'm sure you're more interested in ignoring internal battery losses. So simply measure the DC voltage across the battery, and the DC current, both with a low pass filter.

So that's the DC current flowing through the battery. That's how you obtain the input power, and it's extremely easy.

I'll see about replicating your claim after poynt99 replication results.


poynt99, how close are you to completing your replication?


Regards,
Paul