Claimed OU circuit of Rosemary Ainslie

[henieck]

http://en.wikipedia.org/wiki/Duty_cycle

a duty cycle is a parameter of a pulse train that gives the proportion of HIGH signal to LOW signal.

- I know that - but what is a SIGNAL then? My statement from the above : ...555 timer where you have voltage and current in phase. What are you referring as duty cycle while talking about the Drain? Is it about voltage or current?

- It is obvious for you and me, but they one time take voltage, another time the current for the power calculations or measure the voltage and think that the current is the same (phase) or mix everything the other way around or who knows what else. They need basic course on this. If you take any shortcuts on this they are going to throw you out from the forum again

[ramset]

TK
changes the thread
Headliner on first post by Aaron[just added]
NOTE: DO NOT USE THE CIRCUIT FROM THE QUANTUM ARTICLE. THE CIRCUIT FROM ROSEMARY'S PAPER ON THE EXPERIMENT IS WHAT NEEDS TO BE USED.

[ramset]

 Aaron 
duty cycle
My question was:

Quote:
Originally Posted by Aaron View Post
If the DRAIN has a 3.7% duty cycle, IS IT or IS IT NOT conducting current from a power source for 3.7% of the time per pulse?
Quote:
Originally Posted by poynt99 View Post
The MOSFET switch needs to be set to exhibit a 3.7% ON duty cycle
Quote:
Originally Posted by RAMSET[TK] View Post
NO.
When the drain signal is at battery voltage (high) the mosfet is OFF and the load is non-conducting.

PS - If you want to call the drain signal a 3.7 percent duty cycle, that's OK as long as you know the MOSFET is OFF at that time. Not ON.
Right, but I never mentioned anything about determining 3.7% on by doing the voltage check as explained. Just that if there is a 3.7% duty cycle then the switch is on 3.7% of the time and if the drain is on that long, the whole switch has 3.7% duty cycle.
__________________
With Gratitude, Aaron

PS
TK
when your drinking your frozen coffee watch some of this

http://www.metacafe.com/watch/2820531/don_smith_free_energy/
99 you also please

[TinselKoala]

Thanks again Chet...here's more fuel for the fire

I took Aaron's question circuit and breadboarded it up and shot a video. It's uploading and processing now. 

I am afraid my anger and frustration come through, and I apologize for that.

Now that I have hopefully shown beyond any doubt that the mosfet drain, or the load at point A in the Ainslie circuit, is HIGH when the mosfet is OFF. That is, the duty cycle produced by the original 555 timer circuit causes the MOSFET to conduct 96.3 percent of the time.

And, since AINSLIE has, until this moment, apparently believed that a HIGH signal or voltage here means the mosfet is ON and the load is conducting.....and the energy calculations were based on this mistaken duty cycle number.....well, you do the math.

So the point that I have been trying to make all along is this: Ainslie most probably generated the data in the experiment with a mosfet that was ON and conducting, 96.3 percent of the time.

So it was feeding much much more power to the load than her calculations indicate.
BUT until she tells us FOR SURE what the experiment was actually doing wrt duty cycle, and until she "shows her work" by actually showing how she calculated the energy--not with words but with example equations and results--until then, I think we must conclude that the entire paper is in error and the data invalid.

Not only is there no OU or battery charging here, we have all been wasting our time and money because of Ainslie's strong personality and mistaken ideas about circuitry.

Oh well, I will be able to make a spanky DRSSTC with these mosfets and the Groundloop/Gotoluc H-bridge circuit--which is extremely useful. So all isn't lost.

[ramset]

I haven't seen the vid, but bight your lip these are very sensitive folks no anger just facts
please post a link to the vid
Chet
http://www.metacafe.com/watch/2820531/don_smith_free_energy/
99 you also please