Claimed OU circuit of Rosemary Ainslie

[Harvey]

I too think that MH has nailed it. I favour the shunt (yes definately non inductive!)being placed between the drain and load resistor with all interconnections kept as short as possible. This would physically be the mosfet drain pin connected directly to one side of the shunt resistor, with the other side connected directly to the load resistor.

Hoppy

The purpose of the shunt was to determine the current flowing in to or out of the B(-) post.

It would be better to use an actual current probe at the nodes required.

Also, just to throw this in as food for thought... If a gorilla grabs a man by his suspenders, stretches them really really really fast just below their breaking point...will the mans shoes stay flat on the floor?

It helps us to visualize what may be happening to the battery's 'shoes'. The question then arises as to the differential between the source and the B(-) and how much energy can be made to flow there in 200ns. It becomes even more interesting when we realize that our point of reference is the bottom of the mans shoes 

[poynt99]

The purpose of the shunt is to allow sampling of the instantaneous current in the circuit, period. It has nothing to do with the current specific to any one node. The current should be equal at all points in the loop, therefore it matters not where the shunt is placed. The high side is just as valid as the low side, where it presently is. Most likely the reason it was placed at the Source was for convenience, i.e. it makes the measurement easier by only having to use one scope channel.

A current probe is the obvious choice, but I can't afford the $2k to buy one, and the one other downside to them is most are limited to a 50MHz bandwidth.

Some seasoning for your food: Now, what happens if prior to the gorilla coming along, the man installs a very stiff shock absorber between his shoes and his suspenders?

I know where you're going with that and it has been eliminated in my setup. There was no difference, other than the little "bump" on my "battery" voltage looks more like Glen's now. 

.99

[PaulLowrance]

Note that an current "wave" traversing through a wire wound resistor is traveling almost entirely through the parallel capacitance-- again, antenna theory.

"REAL" power across a load is disipated as heat. 

Regards,
Paul

[PaulLowrance]

FYI, such current waves do not travel at c in a straight *unshielded* wire because of Inductance.

[Hoppy]

Some seasoning for your food: Now, what happens if prior to the gorilla coming along, the man installs a very stiff shock absorber between his shoes and his suspenders?

.99

A damped shock to the crotch I should imagine!

Hoppy