Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[Pirate88179]

Chet:

That is pretty wild.  All I did was run your post through the google translator to get what I posted.  (I do not speak French.)

Probably a good lesson for us here.  Quite a bit different meaning isn't it?  So, someone could make a friendly post in French and we use the translator and think they are saying bad things about our Mother, ha ha.  I had no idea it was that inaccurate.  Talk about lost in translation.

Bill

[Pinoy_Tech]

Question regarding CosmoLV's diagram. What exactly is the PNP transistor doing? It appears to just act as a short across the coil being that the -9v rail is grounded itself. Could anyone explain this?

Respectfully,

Core

As seen on diagram, pin #1 of IC556 appears to be connected to a common ground together with the negative rail on split psu.

If negative rail is grounded itself (other filter cap is useless), my reading to that circuit is that the PNP transistor is almost acting like a damper factor or so called snobber circuit for the coil during collapse just like any other switch mode power supply does (just like fast recovery diode connected in reversed bias), but my understanding to that circuit is a bit different >>>> pin #1 should not be connected to gnd, thus -9V is working as a negative swing for the primary coil (half of supply). Therefore, PNP transistor turns ON when the negative pulse is feed to its base allowing the negative supply to flow to the primary coil. On the other hand, the supply switches to positive swing if NPN trans turned ON while the other turned OFF (push-pull). With that kind of setup, there’s no need to be bifilar coil in primary windings because two Q’s are working symmetrically that flips the supply of the coil to positive and negative rails. However, negative rail can still be connected to gnd if there is electrolytic capacitor connected to the output of Q's before load, just like the ordinary setup for class AB audio amplifier.

of course, it’s just my thinking…       
   -- Pinoy_Tech --

[dllabarre]

As seen on diagram, pin #1 of IC556 appears to be connected to a common ground together with the negative rail on split psu.

of course, it’s just my thinking…       
   -- Pinoy_Tech --

For clarification:

The schematic shows a LM566 not LM556.

Did you get a message from cosmoLV telling you he mis-typed it and it's supposed to be LM556?

DonL

[forest]

Is it possible to run cosmo circuit from single power source like 12V battery ? I don't think that SR913 used dual power supply.

[scratchrobot]

How Camera Flashes Work.

The basic idea is to conduct electrical current -- to move free electrons -- through the gas in the tube, from one electrode to the other. As the free electrons move, they energize xenon atoms, causing the atoms to emit visible light photons (see How Light Works for details on how atoms generate photons).
You can't do this with the gas in its normal state, because it has very few free electrons -- that is, nearly all the electrons are bonded to atoms, so there are almost no charged particles in the gas. To make the gas conductive, you have to introduce free electrons into the mix.

This is the metal trigger plate's job. If you briefly apply a high positive voltage (electromotive force) to this plate, it will exert a strong attraction on the negatively charged electrons in the atoms. If this attraction is strong enough, it will pull the electrons free from the atoms. The process of removing an atom's electrons is called ionization.
The free electrons have a negative charge, so once they are free, they will move toward the positively charged terminal and away from the negatively charged terminal. As the electrons move, they collide with other atoms, causing these atoms to lose electrons as well, further ionizing the gas. The speeding electrons collide with xenon atoms, which become energized and generate light (see How Fluorescent Lamps Work for more information).
To accomplish this, you need relatively high voltage (electrical "pressure"). It takes a couple hundred volts to move electrons between the two electrodes, and you need a few thousand volts to introduce enough free electrons to make the gas conductive.
A typical camera battery only offers 1.5 volts, so the flash circuit needs to boost the voltage substantially. In the next section, we'll find out how it does this.

http://electronics.howstuffworks.com/camera-flash1.htm