Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[Zeitmaschine]

It is very simple: all that is needed is the rectifier and  the DC to 220V/50Hz inverter  .

TK uses an inverter with output power of 5KW? Is this hidden in the tin can?

[yfree]

TK uses an inverter with output power of 5KW? Is this hidden in the tin can?

Bulbs do not need 220V/50Hz to light up, as long as they get the power they need. The output of the tin can is pulsed and not necessarily 50 Hz.

[v8karlo]

TK uses an inverter with output power of 5KW? Is this hidden in the tin can?

Inverter is big blue box device. It serves to convert direct current to 220V sinewave. He is using it
to loop back 200-400mA, 220V to drive his device.
His device has pulsed direct current output. In that video he attached car battery directly to
output of his device. If his device has alternating current output (sinewave) I dont know
what will happen to car battery but it wont be good, trust me, and
in that case he wouldn't be needing Inverter at all.

[27Bubba]

"So this isnt my quest to full you around. I just gived you few new fresh ideas which
has logic in it and can be done without rocket science."

@V8Karlo

And for that, I thank you. Like you said it is matter of time when somebody stumbles at the right combination..

[verpies]

v8karlo has stated that he had not taken a loaded output power measurement, so he presumably took the 900mA - 1100mA output short circuit current (with meter directly across output) and 1200V open circuit voltage stated in his post 13151 and came up with approx 1KW (P=VI). A true power measurement has to be taken with a load and the output power will likely vary with load and the output voltage will of course drop below the open circuit measurement.

P=V*I is a valid calculation only for DC

P=V_rms * I_rms is valid for DC, Pulsating DC and AC only when the voltage and current are in-phase (0 degrees) and both are  measured with RMS meters capable of operating at the crest factor and  frequency of the PDC or AC.

P=V_rms * I_rms *cos(phi) is only valid for sinusiodal AC only when the phase difference (phi) between voltage and current is known and both current and voltage are measured with RMS meters capable of operating at the crest factor and  frequency of the PDC or AC.

If the phi is not zero and the waveform is not DC or sinusoidal then power calculation cannot be made.  It can easily achieve 900% error or more.