Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[Magluvin]

The energy in a linear resonator is accumulated, not generated. In a high Q resonator, the energy can accumulate to the point of resonator destruction. This does not mean that the energy in the resonator exceeded the energy delivered to the resonator.

Well, did the total amount of shaking and motion of the building that Tesla's  tapper box shook, add up to the total amount of energy induced by the tapper, as many times as it tapped? ;]

Would the movement of the buildings girders near the top, have enough force, back and forth, to rewind the spring in the tapper box, to keep the show going all night long? ;]

Mags

[verpies]

The energy in a linear resonator is accumulated, not generated. In a high Q resonator, the energy can accumulate to the point of resonator destruction. This does not mean that the energy in the resonator exceeded the energy delivered to the resonator.

Yes, that's elementary.
I'd like to add that buildings and most coil-capacitor circuits (LCR) are not high Q circuits.

[bass]

Something must be wrong with that value.

I have done a resonance test with exactly this transformer and I get resonance at 50Hz with a 1.34µF capacitor (3 × 1µF in series parallel to 1µF) on the 230V coil. Both 115V coils not connected.

As frequency generator serves a XR-2206 (VCO) set to 50Hz sine wave. The output voltage is 4.3V effective (via push-pull output stage), the oscilloscope shows 12V peak to peak without resonance (direct connected), current is 2.5mA. With resonance (capacitors in series) the voltage on the primary 230V coil goes up to 14V effective, the oscilloscope shows 38V peak to peak, current is 6.14mA.

According to the LC Resonance Frequency Calculator this means the coil of this transformer has an inductance of 7.56 Henry. Measured on the coil the resonant voltage is 3.17 times higher than without resonance. The resonant current is 2.46 times higher than without resonance.

When resonance causes a higher voltage but at the same time draws a higher current from the supply, then where is the Free Energy?

Seems I got my wires crossed, hence what to do next based on these findings?

I had no generator, so selected the capacitor empirically.
If I understand correctly, you have from the generator 12 volts.
Then the power consumption from the generator is equal to 6.14 miliamper * 12V = 0.074 watts. Reactive power in the coil is 6.14 miliamper * 38Volt = 0.233 watts.
Ie reactive power exceeds the power consumption from the generator in 0.233 / 0.074 = 3.15 times

Power consumption from the generator without resonance equal to 2.5 miliamper * 12V = 0.03 watts.
Then the reactive power in the coil at resonance exceeds the power in the coil without resonance 0.233 / 0.03 = 7.77 times.

Check my calculations. If there is an error please inform.

Regards

[xenomorphlabs]

When resonance causes a higher voltage but at the same time draws a higher current from the supply, then where is the Free Energy?

No worries, you only take into account the source voltage for input power considerations like Bass correctly showed in his calculations.
So to say you are not "paying" for the 38 Volt resonant voltage rise, but only for 12 Volt.
In an OU application, the reactive power must be maximized by utilizing hyper-Q resonant circuits (e.g. with hypersaturated iron etc.)
and then only extracting maximally 0.618 (golden cut) of 1.618 (All Hector stuff) ...

[bass]

xenomorphlabs
Please say about developments of Hector. Very little information I found on it.

Regards