Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[Zeitmaschine]

P.S. I don't think it draws more power due to Lenz's Law, I think it draws more power due to Ohms law/power dissipation. Without the effect of Lenz the input would go nut's. And there would be a failure or fire of some kind.

To avoid fire of some kind we are back to this one on page fourteen-O-one:

When the lower coil is switched off by the MC34063 then the back EMF occurs. At that moment the upper coil should be connected through the transistor (green) to the right 1000µF capacitor, so the back EMF can recharge that capacitor. Maybe that schematic is wrong, but I don't think this small device will catch fire due to overunity if it works correctly.

When the lower coil is in ON state then pin 1 of the MC34063 is connected to pin 2 negative. The transistor for the upper coil must be OFF. As soon as the lower coil is OFF pin 1 is HIGH and therefore the transistor for the upper coil must be ON. So why not connecting that transistor (green) with its gate to pin 1 of the MC34063?

[verpies]

But the electrons in a wire are moving. So could a magnetic field deflect electrons from ground into an electric circuit?

Yes, it's called the Hall Effect.

I still don't get it! When a transformer's primary coil is connected to the grid and the secondary coil is shorted, what happens? It draws more current (power) from the grid. Lenz Law.

Yes, Lenz law is "trying" to maintain the magnetic flux inside the winding at a constant level and this has the effect of decreasing the inductance of the primary winding.  In worst case scenario - down to almost zero (just like a straight piece of wire).

Now when a current flows through the coil of a solenoid and then it is suddenly switched off, the back EMF generates high voltage in that coil.

Rather it's the Lenz Law again that is "trying" to maintain the previous level of magnetic flux inside the winding by keeping the current flowing in that winding in the same direction.  Since you are "switching off" the winding, the only way to overcome that switch is to increase the voltage in order to arc over and keep the switch conducting current in the same direction.

Hence the coil of a solenoid has typically a Flywheel Diode connected to it in order to suppress that high voltage. OK.

The switch was in series and the diode is in parallel with the coil.
When the switch opens, the diode provides a path for the current to continue in the same direction through the coil, thereby maintaing the flux level inside the coil.

First question: What happens to the energy that warms up the flywheel diode because of that current going through the diode when there is no diode? Just a high voltage spike does not warm up anything, doesn't it?

It is used up to generate light, EMI and ionize air molecules as well as break down the chemical bonds of the switch contacts.
Whatever current remains (it cannot be completely zero) still goes into resistive heating.

Second question: What could happen when the suppression of that high voltage spike is done by short-circuiting a second coil on the same magnetic core?

The second coil takes over the job of maintaining the magnetic flux level by the virtue of its electric current flow.

That means, we disconnect the primary coil from the current source, then the magnetic field starts to collapse and wants to generate high voltage in both coils. But before that can happen we short-circuit the secondary coil (perhaps by connecting a load to it), not the primary coil. In this case what is the direction of the current and what is the direction of the magnetic field?

The direction of the magnetic field is maintained by the secondary coil.
The direction of current in the secondary coil depends on the direction in which that coil is wound.  If secondary is wound in the same direction as the primary coil, then their current directions are identical.

This is how a flyback "transformer" works. 
First the rising current flowing in the primary winding gradually builds up magnetic flux inside the common core. While the transformer is being charged with energy in that manner, the current in the secondary does not flow because a diode connected in series blocks the secondary current. 

If the diode was shorted, then a simultaneous reverse current would flow in the secondary winding.  This current would work against the the work of the primary winding, that tries to increase the magnetic flux inside the common core. 
...but the diode is there, thus the secondary does not get a chance to oppose the increase of flux being caused by the primary.

Now, when the primary winding is interrupted by some kind of switch, the magnetic flux in the common core had been built up to a high level and must stay at that level somehow (Lenz law).  Since the current in the primary cannot maintain it anymore, the secondary takes over that job. This time the job of the secondary current is to prevent the decrease of the magnetic flux in the common core.  Consequently, the voltage across the secondary suddenly reverses, the secondary diode starts conducting and current starts flowing in the secondary in the forward direction (in the same direction as was flowing in the primary winding - assuming that the primary and secondary were wound in the same direction).

Note, that primary and secondary currents do not flow at the same time in the Flyback "transformer".
In a "true" transformer, those two currents do flow simultaneously -  that is the major difference between these two types of transformers.

When we draw current from the secondary coil of a transformer just at that moment when the primary coil is not connected to the current source then what about Lenz Law? Is it still valid?

Yes, the current "drawn" from the secondary maintains the previous magnetic flux level.

And wouldn't that be a nice job for two thyristors (or transistors)? One connects the primary coil of a transformer to a current source, the other one connects the secondary coil of that transformer to the load. Not at the same time,

If the switch-over is not done simultaneously, then there will be a small time period during which electric current will be interrupted in both the primary and secondary winding. 
Mr. Lenz will run up and say.   Aaaaaa!  Nothing is maintaining the flux level, the flux is falling, we can't have that ! 
What shall we do?  Hmm, the current in the primary winding cannot maintain the flux level because the primary is interrupted, the secondary winding cannot maintain the flux level because the secondary is interrupted.
So enter the panic mode and start increasing the voltage across the primary and secondary windings until the voltage is so high that something breaks down and starts conducting.  Usually it will be the poor transistor or thyristor ...or air ...or insulation.  Something's got to give eventually and start conducting, thereby maintaining the current in one of the windings and consequently the magnetic flux inside it.

[Zeitmaschine]

The second coil takes over the job of maintaining the magnetic flux level by the virtue of its electric current flow.

Thanks for that profound answer. But my point is this: The connected primary coil creates a magnetic field in the core of a transformer. Now we disconnect that coil and quickly connect a load to the secondary coil. Then the collapsing magnetic field generates a current through that coil and the load. So the load is running actually on a collapsing magnetic field rather than on a building magnetic field. When the field has collapsed it is zero and the current stops to run trough the secondary coil. Now we connect the primary coil again and disconnect the load from the secondary coil. That means the power source that provides the current for the primary coil »sees« each time it is connected just an idle running transformer with no load connected to the secondary coil. Thus in that operation mode that transformer should only need the current as if it were not connected to any load on the secondary coil (idle) when in fact it is connected to a load.

But maybe I'm confusing here something ... 

[stivep]

http://youtu.be/e92yz5Y1img


or the same video  at:


http://www.youtube.com/watch?v=e92yz5Y1img&feature=youtu.be








Wesley

[Farmhand]

Thanks for that profound answer. But my point is this: The connected primary coil creates a magnetic field in the core of a transformer. Now we disconnect that coil and quickly connect a load to the secondary coil. Then the collapsing magnetic field generates a current through that coil and the load. So the load is running actually on a collapsing magnetic field rather than on a building magnetic field. When the field has collapsed it is zero and the current stops to run trough the secondary coil. Now we connect the primary coil again and disconnect the load from the secondary coil. That means the power source that provides the current for the primary coil »sees« each time it is connected just an idle running transformer with no load connected to the secondary coil. Thus in that operation mode that transformer should only need the current as if it were not connected to any load on the secondary coil (idle) when in fact it is connected to a load.

But maybe I'm confusing here something ... 

To simplify that we only need one switch, a coil, a diode and a load, or all together a "Boost converter", the coil gets charged with no "load" then it discharges to a higher voltage with the load attached, so the load is run from the "field collapse". Here's the problem as I see it, many of us use terms differently, to me "Back emf" is the same as "counter emf" and happens in any wire or coil any time a current is flowing in it ( but only when the current is flowing ) the back emf or counter emf first happen together with the applied emf when the coil is charging.

But to "me" the energy released from the coil's magnetic field when the coil is switched is the "inductive energy release" or "the coil discharge" this happens after the coil is switched off from the supply. And being that there is current and wire involved in most cases of coil discharge then as the coil discharges and current flows, the current in that instance also get's a visit from Mr Lenz, meaning the coil discharge also faces back emf or counter emf in the conductor it flows through.

In HF circuits this (exchange between magnetic field and current) is the root cause of ringing in the wires in the circuitry and why they need to be kept short.

Cheers

P.S. Believe it or not I made a solar battery conditioner that produced such powerful cap discharges into a battery which caused rapid current spikes of several amps through a pair of wires about 1 meter long and the ringing in the wires could be heard as well as picked up on my scope as a radio signal. EMR or EMI was too much without some shielding.
The sudden discharges caused an effect that could make some people ill. And it was random frequency based on power supplied.

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