Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[MenofFather]

Thanks for this Nice summary of the vid, Vortex1

But in 15 W in input and 15 W in output before the additional light bulbs with 7 W (even if would still need light bulb "unit" lit with its nominal voltage for comparison of the different brightnesses), wouldn't be already overunity? 15 + 7 = 21, 21/15 =~ 1.5 of COP?

No. One light probarly light on 0.3 of it power, other of 0.6 of it power. If two is 15 W laamps, then 15x0.3 + 15x0.6=4.5+9=11.5 W. So in is 15 W out is 11.5 W.

[zcsaba77]

No. One light probarly light on 0.3 of it power, other of 0.6 of it power. If two is 15 W laamps, then 15x0.3 + 15x0.6=4.5+9=11.5 W. So in is 15 W out is 11.5 W.

Both can be true OU or underunity, but he shown ampmeter on inputside, and action follow reaction if draw more on output side, must show on inputside measurments, or energy is stored in device? or what? so misterios.

[Vortex1]

True we cannot know the brightness of the lamps and what % power they are consuming. This is just a guess.

The important part of the video is the induction of a current flow in the copper bar. I estimate the coupling capacitance to the first coil layer to be not more than a few hundred picofarad. At 20 kHz, even with square waves it would be very difficult to light a lamp as there is an insufficient closed circuit through the capacitance.

More important to observe is the lack of load reflection back to the power supply.

I can understand if he were pumping in a few hundred watts, it is easy to shift a few watts from some other lossy element into the lamp and not have it show on the metering, but we are talking a power input too small to hide the extra power drain.

[Free.Energy]

True we cannot know the brightness of the lamps and what % power they are consuming. This is just a guess.

The important part of the video is the induction of a current flow in the copper bar. I estimate the coupling capacitance to the first coil layer to be not more than a few hundred picofarad. At 20 kHz, even with square waves it would be very difficult to light a lamp as there is an insufficient closed circuit through the capacitance.

More important to observe is the lack of load reflection back to the power supply.

I can understand if he were pumping in a few hundred watts, it is easy to shift a few watts from some other lossy element into the lamp and not have it show on the metering, but we are talking a power input too small to hide the extra power drain.

Agreed.  It does not appear to be coupled magnetically.

[Khwartz]

Hehe, yes!  The copper bar remembers me the often proved apparently and much documented overunity "Vialle Effect" One even been done with ferrites around the copper bar... except in the Vialle's Autogenerator, there is a gap as the bar is cut in two equal peaces and insulated from each other.