Flynn's Parallel Path

[jake]

If you analyze the "Simple Magnetic Force Multiplication Experiment", using the principles of magnetism spelled out by Flynn, the results of the experiment are not surprising or astounding.

The formula for force in magnetisim (per the Flynn site, and presumably common accepted knowledge) dictates that the attractive force increases with the square of the flux.

Now if we look at the forces in the experiment and relate flux values to them we get the following:

Lets assume 421 grams = 1 unit flux
If we add another unit of flux (one more permanent magnet), per the above formula, we should expect exactly 4 times the lifting force (2 times 2, or 2 squared) which would be 1684 grams.

The actual experiment result was 1721 grams, which would indicate that the second magnet was just slightly stronger than the first magnet.

So far, what has happened is exactly what would be expeced.  We doubled the flux, and quadrupled the force.  If there is anything telling at this point, it is that 100% of the flux from the top magnet is acting on the bar across the bottom. (without any "steering")

Now, to go from the 1721 grams of force in the second diagram to the 3845 grams in the third figure would require:
(3845/1721)^0.5 = 1.494 times the flux that we have in the second diagram.

In the second diagram (1721 grams) 2.02 units flux are present: (1721/421)^0.5=2.02

This means that the third diagram would have 2.02 * 1.49 units of flux, which equals 3.02 units of flux.  Can also be computed as a ratio of diagram 1: (3845/421)^0.5 = 3.02 as a back check on the figure.

Since we have 2.02 units of flux in the second diagram, and 3.02 in the third diagram, we should have to add 1 unit of flux to arrive at the 3.02 units of flux that would be required to give us the 3845 grams of lift.

Everyone follow me so far?

This means that the electric windings are adding exactly the equivalent of 1 unit of flux to the system, which would be expected to give the zero force at the top, effectively "switching off" the top magnet, right?

Now we go to the last figure.  This figure shows that we are applying electrical current that would produce 1091 grams of force, which would require (1049/421)^0.5 = 1.58 units of flux.

What all this adds up to is we are applying electrical current to the circuit that equates to 1.58 units of flux, as proven by the right diagram in the experiment.  The net gain we are getting from applying current that should produce 1.58 units of flux is only 1.0 units of flux in the third diagram.

The upshot is, we are applying enough current to the circuit to expect a much larger lifting force that we actually get.  If the 1.58 units of flux being generated in the circuit on the left were added to the 2 units of flux in the second circuit, we should see 3.58 units of flux, or 5396 grams of force in diagram 3.

If we take the information from this experiment and analyze what would happen if we attempted to use it to make a "super transformer", we can also predict what would happen.

There is no arguing that we have fundamentally 3 uints of flux in diagram 3, with the current applied.  By putting a bar across the top we can prove that there is no flux available at the top of the circuit.  (see Flynn documents showing zero force on the top bar).  Now, if we reversed the polarity, we would have 3 units of flux at the top, and 0 at the bottom.

If we put a bar across each end, with a coil around each bar, can now create a current in the coils, which is based upon the change in flux passing through the coils.  Each coil will oscillate between 0 units of flux and 3 units of flux as we alternate the current to the coils.  This gives us a delta of 3 units of flux in each coil, by applying electricity that would create 1.6 units of flux.

Now lets take the magnets out of the circuit.  We now have figure 4, but add the coils at each end of the circuit.  This circuit differs in that the magnetic flux will completely reverse as we alternate the current to the input coils.  Since it alternates (because the permanent magnets are not there to "redirect" the flux), we will oscillate from +1.6 units of flux to -1.6 units of flux (complete flux reversal at both ends).  This means that the coils will see a delta of 3.2 units of flux without the magnets in the circuit.

What this means is the permanent magnets actually make the transformer less effective by the ratio of 3.2 to 3.0, or about 93.5 percent.

Thus, I predict that if someone makes the circuit shown and adds the coils at each end and makes it so that it can have the magnets put in and taken out, that the transformer would work about 6.5% better by leaving the magnets out.

If you look at what has to happen in the circuit, all of the results make sense.  To get from 2 units of flux to 3 units of flux requires that the electric coils drive 1 unit of extra flux through the top permanent magnet to get it around to the bottom of the circuit.  Since the magnet is already providing 1 unit of flux, this effectively doubles the flux that must pass through the upper magnet.  This probably explains why they warn that Nib magnets are not good for this experiment.

I'm not saying all this to imply that the Flynn circuit is useless, but to point out that it is probably not magic.  Upon analysis the circuit works just the way it should.

[Elvis Oswald]

The power to generate 1.6 units of flux will only produce 1.6 units... that's why it's called "the power to generate 1.6 units of flux.    That's the first thing you're missing.  In a regular transformer... with equal windings on both coils.... power out = power in (best case)
So your estimate of power out of a regular transformer is wrong.

If you are correct on the math about the transformer with pp... then the power out should be almost double.  And since that jives with my abstract calculations, I would say that we are looking at doubling power with a simple transformer.

[jake]

Elvis,

My math says that if you get 1.0 without the magnets, you will get 0.93 with the magnets, so my math doesn't jive with your abstract calculations.

I encourage you to build the device and test it.

The first thing you are missing is that the 1.6 units of flux completely reverses when you reverse the polarity on the input coils when the magnets are not in the circuit.  This gives a change of 3.2 units when the magnets are not present (+1.6 - (-)1.6 = 3.2)   With the magnets in the circuit, the flux does not reverse through the secondary coils when you reverse the polarity of the input coils.  It simply varies from 0 to 3.0 for a change of 3.0.  This is a diminishing return by having the magnets present in the circuit.  (The transformer output voltage is proportional to the flux change through the output coils)

[Elvis Oswald]

What you are still missing is that - IF you use your example, and the output is 3.2... then you applying enough power to provide 3.2...

So stick the 3.2 into your first calculation and see how it changes.  Because the input is the same setups... and the input is "enough power to generate 3.2"  And that's not what you used in your first example.  You used enough power to generate 1.6.
You should have said it was +.8 and -.8 to equal 1.6

[jake]

Elvis,

Respectfully, build it and prove it to yourself.