Second Stage Joule Thief Circuits

[PaulLowrance]

I just replaced gadget's right capacitor with a rechargeable battery; And charged it.  Oddly enough, I'm not using his circuit layout, simply the standard joule thief with the "Capacitor Appendage" that Gadget added minus the heater wire and switch.  ( i'm limited creatively here ).  Voltage started at 0.988volts and is now sitting at 1.207 down from 1.271 an hour ago when I pulled it off.  Source voltage started at 1.233 and is stable at 1.221.

If I understand you correctly, and you gave the batteries sufficient rest period to settle down, then that's incredible. The AA source battery started at 1.233V, ended at 1.221V, and the charge battery started at 0.988V, ended at 1.207V? I'm wondering if we can get another person to replicate this, perhaps Yucca. Eventually I'll start building one as well.

Paul

[Pirate88179]

Yes, those spikes can charge a battery ala Bedini but, as I found out a while back, those spikes are saved as usable power in a super capacitor and, as gadget is saying, in the boostcap as well.  This is what I found when I first hooked one to my JT circuits and then to my EER.  They charge really fast and you get real power out, not just volts.  It is amazing.

Bill

[Groundloop]

@jadaro2600,

>>"How does your ( future ) circuit know when the capacitor is fully charged?"

If you look at my posted add on circuit for the JT you will see that there is two SCRs.
The bottom one (T1) is biased from the voltage over the super capacitor via two
1N4007 diodes. The voltage drop in the 1N4007 is 0,7 volt each (approx.).
Then you have two resistors limiting the trigger current going to the T1.

When the super capacitor charges up, the voltage for the trigger of T1 will at some
point reach more than 1 volt. The R2 (10K pot) is adjusted so that the trigger current
at that point is above the minimum required trigger current for the TIC106 to switch on.
This will connect the load to the super capacitor and the super capacitor will discharge.
When the current through the T1 has fallen to less than some mA then the TIC106 will switch
off again, and the cycle will repeat.

Now, the other SCR (T2) is there to give a little feed back to the AA battery.
The 1N4007 diode drops the volt 0,7 volt. The R4 (10K pot) is adjusted so that
the SCR will trigger when the voltage over the super capacitor reach 2,6 volt (approx.)
The voltage in the AA will rapid increase and when the voltage in the AA is higher than the
voltage on the other side of the SCR (near the 1N4007) then the current through the SCR will
stop flowing and the SCR will switch off. This will top up the AA battery each time it has fallen
below the threshold level. D4 will be a BY255 on the new circuit.

The aim of the circuit is to let the super capacitor charge up to 2,6 Volt each time before
discharging it to the load.
I apologize for being a little "short" last night, but it was late at night and I also have a day job
to take care of.

I hope this answered your questions.

Groundloop.

[innovation_station]

heat!

i can melt carbon rods .. i have melted stainless ...  but trust me you do not want that ..

worst way to do it .. this is why the coliders keep getting tampered with ... 

fire it up and call a solar flare    duh!   

less you like radiation and x ray ..    plus it will damm near blind ya! it is so powerfull

i burn big diodes up  like 1000v 4 amp or something fr diodes too boot !

answer no! to heat ...  unless you do it gadgets way off the output cap

a video

ra!

RA AH AH AH!  O LA LA GA GA! HOT!    BAD ROMANCE!

http://www.youtube.com/watch?v=ACm9yECwSso

BTW BORG EYE IS ONLINE  OR WAS ..   i could feel the darn thing .... AKA   K BASE..    you could tell when it got turned on ... i almost told some how to tp to the hollow earth ...  with out coils.. 

yikes..  quick turn it off...    oops

look at what she wheres on my dark eye..  she i think may be re...  lol 


i was ra!  not now



btw do not do that agin!   unless im wearing my belt ..  the streem is too fast!

whats the belt

12 and 1 ring a bell 

[Magluvin]

Not to break up the scuffle, or maybe it will for a post, but I was thinking what I said earlier about the number of electrons is directly related to the voltage across the cap.
I should have probably said, when a capacitor has no charge potential between 2 plates, 0.0000000v, the number of electrons in each plate should be equal, in theory of course. One or both plates could have more or less electrons due to static charge, but we will ignore that for our purposes.

When a voltage potential difference is introduced across the capacitor, one plate will be loaded with excess electrons, and the other plate will be depleted of electrons, and the number of electrons gained on the excess plate, should be the same as the number of removed electrons from the depleted plate, and that number is directly related to the voltage potential difference across that cap, at the time. Much better, dont you think? =]

If a transformer, inductor, (current source) is producing that voltage across the cap, then we can say that the electrons are transferred from one plate to another, till the caps charge is equal to the voltage source. But if we have a battery as a voltage source, the electrons taken from one plate, will not be the same electrons forced into the other plate. The depleted plate electrons will be pulled and stored only on the positive terminal side of the battery, and the excess plate electrons will only come from the negative terminal side of the battery till the charge voltage potential on the cap is equal to the battery voltage. The electrons dont move through the battery from one side to the other unless a conductive path exists from the positive to the negative terminals externally. Ignoring leakage of course. Theory.

There you have it. Its deep, but a better explanation of what is actually happening. Thought that might get some real discussion going again here and break up the rhetoric. A 650 farad cap is quite huge in terms of charge and can produce "instantaneous" currents soo much higher than any battery.
I have a 50 farad 20v cap in my Fiero installed after a Jacobs Accuvolt voltage regulator that can regulate up to 100 amps continuous, but with "The Cap"  thats what they call it, I can have over 200 continuous amps, regulated available. The Jacobs can be set from 12v up to 16v, via 10 turn pot.
You may ask, Magfrikinluvin, are you going "Back to the future" with that thing?  lol   I am into serious custom car audio. I use older Soundstream Class A amps(not quite class A, nor tube amps, but they are the sweetest amps I have ever heard in a car) The PS in these amps are unregulated and giving them 15.9v reg. input can give me much more power than the 12v rms ratings on the amps. The peak clean output of these amps are not restricted to regulated rail voltages. The rail voltage of a loosely regulated PS in a car amp is 50 to 75% higher than a regulated PS amp of the same RMS ratings at 12v. Most music is peaks so you get more voltage to the speakers most of the time this way. A regulated PS amp will clip at the rms rail voltage, but unreg rails will be quite higher most of the time, thus more clean power.
Thus my reasons for me cap.
This cap comes with a 100 amp relay to disconnect when ignition is off due to leakage inherently in The Cap so it wont discharge the battery(8 yr old tech). Using 4awg power and gnd wire from the battery to the cap, when that relay connects the cap, the 4awg wire twitches. And it tells you that will happen in the caps user manual. Sick.
I run my whole electrical system in the car off of the setup, except the alternator and starter. My lights are bright, my fans are belowin, my windows are up and down faster than any fiero, and the spark at the plugs is babam. Fuel pump has more pressure. etc. I love it.

Ok  sorry for going way off track.  All that from and attempt to correct my earlier quote. =]

Mags