Second Stage Joule Thief Circuits

[nievesoliveras]

This is a simpler solution but the parts must be of a quality to withstand the amperage you mentioned.

This is used on the wind turbines as a shunt regulator. Maybe it works on your project.

Jesus

[nievesoliveras]

Lets imagine that the amperage going through the transistor is 850A at 2.7v
The transistor uses a small current to move a large one. 100 to 1 I think.

850A/100=8.5A

The formula to get the resistance is R=V/I so:

2.7V/8.5A=0.317647 ohm

So something is wrong here. Is there anybody that can help on this?
I think that that one is a too small resistance for the task.

Jesus

[gadgetmall]

ok i get it . so i could put a 2.5 volt zener on the cap output and when it reached that it would fire the cap into the battery . Well i could go further and put a 1.6 volt zenar in series with the battery to keep it from over charging . I see the problem and the Bcap not wanting to release the scr  after it reaches 2.5 volts because it is so much higher and wont take that long before the battery fries with that amount of amperage across the AA cell . It Might work on a cap to cap system thought . I will see if i can build this and report whats it doing . Anyway Very Good Suggestion and Alex will probably consider this one or maybe already has .

Thanks . I admire your Schematic skills

Albert

[Pirate88179]

I vote and nominate Jesus as "Mr. Schematic".  He does do a wonderful job.

Bill

[jeanna]

Lets imagine that the amperage going through the transistor is 850A at 2.7v
The transistor uses a small current to move a large one. 100 to 1 I think.

850A/100=8.5A

The formula to get the resistance is R=V/I so:

2.7V/8.5A=0.317647 ohm

So something is wrong here. Is there anybody that can help on this?
I think that that one is a too small resistance for the task.

Jesus

I think it is more like 30 milliamps becomes 3 amps. But before you do that you need to go around the circuit and subtract all the things that take 1 volt like the resistors and diodes.

I do not know if this will help, and
I cannot do it, but I think this is where to look.

jeanna