Joule Thief 101

[tinman]

Chet:

Here, go ahead and please complete the current loop from Brad's diagram for the red dots for after the transistor has switched OFF.  The current starts in the right L1 coil moving from top to bottom.  Please mark up the diagram showing the full current loop and settle it once and for all.  Fulfill your destiny as a mother hen.

To quote your illustrious experimenter Brad, "Im not going down this babying road with you MH. If you cannot work out where the current flow continues from where the marked dot's are,then you clearly do not belong here."

MileHigh

Chet

Dont bother with this question,as it is another of MHs loaded question's,that have no right answer.
He is asking you to complete the current path of the red dot's,but says that this path starts at the top of L1,and moves from top to bottom--as in the path of the blue dot's.

This diagram was in relation to my JT circuit that had MHs !!death spike! of reverse current at the base of the transistor during the transistors off period.

He cannot answer this question of his correctly him self,as it cannot be answered correctly going by his description of the question.
This is a loaded question he has put to you ,as he knows that you will never be ablet to answer it correctly--or so he think's.


So dont fall for this garbage question--it's about as good as his wine glass resonance questions--which he himself also cannot answer,nor has done so.


Brad

[MileHigh]

Brad:

If we look at the schematic below,i have drawn in two options for L2s current path.
The red dots show the current flowing back into the battery.
The blue dot's show the current from L2 flowing into L1.
It is my belief that the later is correct,and that the current flowing through L2 flows into,and is additive to the current flowing through L1,and the LED.

We are talking about the event of the transistor collector-base junction breaking down and current being observed flowing in the reverse direction through the base.  The source of the current flow causing the breakdown of the junction is L1.  So when you talk about the "two options for L2s current path" anybody that has a Brad Secret Decoder Ring knows that what you are really saying is the "two options for L2s current path after that current is supplied from the discharge from L1."   It's just the usual scrambled brains in action.

You have avoided responding to this issue because Dr. Brainfry is supposedly infallible.  Push has come to shove and instead of acknowledging that you failed to think through your statements before you posted them and admit that you were in fact wrong, now you are instead having a good freak out and going nuts in an attempt to still not admit that you are dead wrong.  Dr. Brainfry is having a brain seizure.

MileHigh

[MileHigh]

his wine glass resonance questions--which he himself also cannot answer,nor has done so

The wine glass resonance questions can be answered and they will be answered in due time.  This is your bad karma from when I asked you for where something was that you had posted earlier in the thread and like a rude jackass you repeatedly refused to point me to some unlabeled content in one of your own postings.  You thought that it was a big joke to outright refuse my simple requests for showing me where something you had posted was and you got your jollies from repeatedly refusing my requests and from when I had to read though a big chunk of the thread to find it.

So you are waiting because you were a rude discourteous smug little jackass and you thought it was funny to refuse my simple requests multiple times.  And lo and behold it turns out that Dr. Brainfry can't answer two simple questions about a simple resonating wine glass after all of his big talk about resonance.  So you can continue to sit on the spot and fry.  You are just going to have to wait some more, karma is a bitch when you act like a rude smug little jackass and sometimes it bites back.

[tinman]

Brad:

We are talking about the event of the transistor collector-base junction breaking down and current being observed flowing in the reverse direction through the base.

  Dr. Brainfry is having a brain seizure.

MileHigh

Wrong

Try again.
Lets see who has the brain seizure.
The first scope shot is of your death spike.
The second scope shot is showing the trace over a 1 ohm CVR at the collector.
I have placed the ch2 probe at the base,so as you can see where the timing of the !!death spike!! is
Where is this current flowing through the collector,that flows into the base via this junction breakdown of your's?.

Brad

[MileHigh]

Wrong

Try again.
Lets see who has the brain seizure.
The first scope shot is of your death spike.
The second scope shot is showing the trace over a 1 ohm CVR at the collector.
I have placed the ch2 probe at the base,so as you can see where the timing of the !!death spike!! is
Where is this current flowing through the collector,that flows into the base via this junction breakdown of your's?.

Brad

Wrong my ass.  The cycle time is 75 microseconds for one trace (spike) and 60 microseconds for the second trace (collector).  You don't even show how the first trace was made.  Was the CVR for the collector trace in the same place when you captured the spike trace?  Or did you have two different circuits for each test and that's why the cycle time is different between the two?  Oops you don't say anything about that and even the best Brad secret decoder ring can't help in this situation.  Why didn't you put the CVR for the collector trace on top of L1 so that you would not disturb the equipotential between the LED anode and the collector because preserving that equipotential might be important?

You are second-guessing our mutual original conclusion (yourself, myself, Picowatt) about the death spike and now you are questioning me about your own second guessing?  Remember in your ever present quest to insist that you are never wrong that you were insisting that the reverse current spike was normal?  Did you even try to reduce the number of turns in L2 to see if the reverse current spike would go away in the original setup?  Brain fry indeed.

Not surprisingly and as expected Brad, what you have shown is incomplete and it is a complete shambles.